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3 years ago

HELP HELP HELP HELP HELP HELP HELP PLEASEEEEEEEEEEEEEEES

Mathematics

1 answer:

Akimi4 [234]3 years ago

4 0

Answer:

600

Step-by-step explanation:

6 x 6 x 10 = 360

6 x 4 x 10 = 240

360 + 240 = 600

Multiply base times height for area of triangle, multiply that by the depth (10m)

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WITCHER [35]

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2 years ago

Integration by Parts Evaluate e-2x cos(2x) dx.

kifflom [539]

Let

$I = \displaystyle \int e^{-2x} \cos(2x) \, dx[/]texIntegrate by parts:[tex]\displaystyle \int u \, dv = uv - \int v \, du$

with

$u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \cos(2x) \, dx \implies v = \dfrac12 \sin(2x)$

Then

$\displaystyle I = \frac12 e^{-2x} \sin(2x) + \int e^{-2x} \sin(2x) \, dx + C$

Integrate by parts again, this time with

$u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \sin(2x) \, dx \implies v = -\dfrac12 \cos(2x)$

so that

$\displaystyle I = \frac12 e^{-2x} \sin(2x) - \frac12 e^{-2x} \cos(2x) - \int e^{-2x} \cos(2x) \, dx + C\\\\ \implies I = \frac{\sin(2x)-\cos(2x)}{2e^{2x}} - I + C \\\\ \implies 2I = \frac{\sin(2x) - \cos(2x)}{2e^{2x}} + C \\\\ \implies I = \boxed{\frac{\sin(2x) - \cos(2x)}{4e^{2x}} + C}$

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2 years ago

Select the best answer for the question

artcher [175]

Answer:

HOWEVER: "Less Than" is usually depicted as a dashed line at the border. and there MUST be an OR between these two equations to include all of the blue area. An "and" there would exclude the area between the edge lines.

Step-by-step explanation:

2x + y < 10

y < -2x + 10

3x + 2y < 12

2y < -3x + 12

y < -1.5x + 6

3 0

3 years ago

14% of 980?

Natasha2012 [34]

137.2
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$298.30
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5970
3050
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150
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3 years ago

Solve log x = 4!!! Please

Lisa [10]

I think the answer is .602050

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3 years ago

Read 2 more answers