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Dahasolnce [82]
3 years ago
9

Choose the quadrant in which the terminal side of this standard position angle is located:

Mathematics
1 answer:
nikklg [1K]3 years ago
3 0
The correct answer is a,c,d
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Which relation is a function?
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<em><u>{(-1, -2), (1, 3), (1, 5), (3, 5)}</u></em><em><u>.</u></em>

<em>[</em><em>that's</em><em> </em><em>it]</em><em>:</em><em>)</em>

8 0
2 years ago
Carlos makes a shade of orange clay by mixing 18 grams of red clay with 3 grams of yellow clay. Anaya wants to make the same sha
GrogVix [38]

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6

Step-by-step explanation:

6 0
3 years ago
A scientist claims that 7% 7 % of viruses are airborne. If the scientist is accurate, what is the probability that the proportio
Reptile [31]

Answer:

The probability is P(|p-\^{p}| >  0.03)  =   0.0040

Step-by-step explanation:

From the question we are told that

   The population proportion is p =  0.07

   The mean of the sampling distribution is   \mu_p =  0.07

   The sample size is n = 600

Generally the standard deviation is mathematically represented as

     \sigma_p  =  \sqrt{\frac{p (1 -p)}{n} }

=>    \sigma_p  =  \sqrt{\frac{0.07(1 -0.07)}{600} }    

=>    \sigma_p  =  0.010416    

Generally the probability that the proportion of airborne viruses in a sample of 600 viruses would differ from the population proportion by greater than 3% is mathematically represented as

      P(|p-\^{p}| >  0.03) =  1 - P(|p -\^{p}| \le 0.03)

=>   P(|p-\^{p}| >  0.03)  =  1 -  P(-0.03 \le p -\^{p} \le 0.03 )

Now  add p  to  both side of the inequality

=>   P(|p-\^{p}| >  0.03)  =  1 -  P( 0.07-0.03  \le \^{p} \le 0.03+ 0.07 )

=>   P(|p-\^{p}| >  0.03)  =  1 -  P(0.04 \le \^{p} \le 0.10 )

Now  converting the probabilities to their respective standardized score

=> P(|p-\^{p}| >  0.03)  =  1 -  P(\frac{0.04 - 0.07}{0.010416}  \le Z \le \frac{0.10 -0.07}{0.010416}  )

=> P(|p-\^{p}| >  0.03)  =  1 -  P(-2.88  \le Z \le 2.88 )

=>   P(|p-\^{p}| >  0.03)  =   1 - [P(Z \le 2.88) - P(Z \le -2.88)]

From the z-table  

       P(Z \le 2.88)  =  0.9980

and

       P(Z \le -2.88)  = 0.0020

So

     P(|p-\^{p}| >  0.03)  =   1 - [0.9980 - 0.0020]

=>   P(|p-\^{p}| >  0.03)  =   0.0040

     

7 0
3 years ago
For the love of God help me
Andrej [43]
A) Let b and r represent the cost of a bag of bark mulch and red mulch, respectively. (Always start with a "let" statement that defines your variables--usually based on what the question is asking: cost of each type.)

8b +6r = 44.50 . . . . Paul's first purchase
1b +8r = 25.50 . . . . .Paul's second purchase


b) There are many ways to solve a set of linear equations like this. I like a graphical calculator because it gives me the solution without having to think too much or do any arithmetic.

(b, r) = (3.50, 2.75)

Pine bark mulch costs $3.50 per bag.
Red mulch costs $2.75 per bag.


c) The project cost would have been
.. 14*$3.50 +10*$2.75 = $76.50

Paul would NOT have been able to make that purchase with funds available.

4 0
4 years ago
Find the geometric mean of 24 and 45.
Sveta_85 [38]
Hi! It’s 10 to the square root of 6.
7 0
3 years ago
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