Since the degree of the angle is 45, we know that the triangle is isosceles. That means that the sides of the triangle, not including the hypotenuse, has a length of 3√2.

Using the Pythagorean theorem, which is a^2 + b^2 = c^2, we have (3√2)^2 + (3√2)^2 = c^2.

Note: c is the hypotenuse of the triangle.

18 + 18 = c^2

= 36 = c^2

Therefore, c = 6.

3 0

2 years ago

Domain of y=3secx/4 is

sladkih [1.3K]

Umm I didn't get a domain.... No solutions were found...

3 0

2 years ago

There are approximately 7.7 billion humans on Earth. If the virus spreads beyond the 200-person town, how long will it be until

eimsori [14]

Answer:

25.2 weeks until everyone on the planet is infected

Step-by-step explanation:

The number of infected people after t weeks has the following format:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the initial number of infected people and r is the growth rate, as a decimal.

The number of infected people doubles every week

This means that $P(1) = 2P(0)$

$P(t) = P(0)(1+r)^{t}$

$2P(0) = P(0)(1+r)$

$1 + r = 2$

$r = 1$

$P(t) = P(0)*(2)^{t}$

200-person town

This means that $P(0) = 200$

$P(t) = P(0)*(2)^{t}$

$P(t) = 200*(2)^{t}$

How long will it be until everyone on the planet is infected?

This is t for which P(t) = 7700000000[/tex]

$P(t) = 200*(2)^{t}$

$7700000000 = 200*(2)^{t}$

$2^{t} = \frac{7700000000}{200}$

$\log{2^{t}} = \log{\frac{7700000000}{200}}$

$t\log{2} = \log{\frac{7700000000}{200}}$

$t = \frac{\log{\frac{7700000000}{200}}}{\log{2}}$

$t = 25.2$

25.2 weeks until everyone on the planet is infected

4 0

3 years ago