Answer:
I'm pretty sure the answer is A
Answer:
A customer who sends 78 messages per day would be at 99.38th percentile.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Average of 48 texts per day with a standard deviation of 12.
This means that
a. A customer who sends 78 messages per day would correspond to what percentile?
The percentile is the p-value of Z when X = 78. So
has a p-value of 0.9938.
0.9938*100% = 99.38%.
A customer who sends 78 messages per day would be at 99.38th percentile.
Answer:
200
Step-by-step explanation:
.75x=150
150/.75=x
200=x
Answer:
x ≈ 13.5
Step-by-step explanation:
Using the tangent ratio in the right triangle
tan34° = = ( multiply both sides by 20 )
20 × tan34° = x , then
x ≈ 13.5 ( to the nearest tenth )
Answer:
x + 2/3=29/5
x=29/5 - 2/3
x= 77/15
i don't know if this is what you're asking for.
sorry if its not