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il63 [147K]
3 years ago
9

I picked the yellow one, was I correct?

Mathematics
1 answer:
nikitadnepr [17]3 years ago
5 0

Answer:

the answer was 9 (red)

Step-by-step explanation:

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last month leonardo went to the gas station 5 times to buy gas for his car the numbers of gallons he purchased were 14.071, 14.3
zavuch27 [327]

Answer:

its 14.32

Step-by-step explanation:

because if you line all the numbers up and you look in the hundreds place 3 is the biggest number

8 0
3 years ago
Can I get an answer please ​
Verdich [7]

Answer: 1, 4, -7

Step-by-step explanation:

Coefficients are numbers that are in front of a variable. Let's first determine the terms that have variables in them.

z, 4z², -7a

Since these all have variables in the terms, we know the coefficients are 1, 4, -7.

8 0
3 years ago
Which of the following statements demonstrates the associative property of multiplication?
professor190 [17]
Associative property of multiplication means that it doesn't matter where the parentheses are placed because it will still be the same answer.  

So your answer would be 1, 4 x (3 x 6) = (4 x 3) x 6

I hope this helps! 
6 0
3 years ago
Use a linear approximation (or differentials) to estimate the given number. (Round your answer to five decimal places.) 3 217
Soloha48 [4]

Answer:

f(216) \approx 6.0093

Step-by-step explanation:

Given

\sqrt[3]{217}

Required

Solve

Linear approximated as:

f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)

Take:

x = 216; \triangle x= 1

So:

f(x) = \sqrt[3]{x}

Substitute 216 for x

f(x) = \sqrt[3]{216}

f(x) = 6

So, we have:

f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)

f(215 + 1) \approx 6  +1 \cdot f'(x)

f(216) \approx 6  +1 \cdot f'(x)

To calculate f'(x);

We have:

f(x) = \sqrt[3]{x}

Rewrite as:

f(x) = x^\frac{1}{3}

Differentiate

f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}

Split

f'(x) = \frac{1}{3} \cdot \frac{x^\frac{1}{3}}{x}

f'(x) = \frac{x^\frac{1}{3}}{3x}

Substitute 216 for x

f'(216) = \frac{216^\frac{1}{3}}{3*216}

f'(216) = \frac{6}{648}

f'(216) = \frac{3}{324}

So:

f(216) \approx 6  +1 \cdot f'(x)

f(216) \approx 6  +1 \cdot \frac{3}{324}

f(216) \approx 6  + \frac{3}{324}

f(216) \approx 6  + 0.0093

f(216) \approx 6.0093

6 0
3 years ago
The radius of a circle is 20cm. What is its area? ( ratio= 3.14)<br><br> ​
Musya8 [376]

Answer:

A=100π=314.16 cm 2 to 5 significant figures

Step-by-step explanation:

6 0
3 years ago
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