3x^4 becomes 3(3x)^4=3*3^4*x^4
y^2 becomes (3y)^2=3^2y²
the new z=3² the old z, so b is correct.
Answer:
I believe it is c> 34
Step-by-step explanation:
Correct me if i'm wrong
9. <span>1.25 = (1 x 1) + (2/10) + (5/100)
11. is ---C----</span>
Answer:
Let d be the remaining distance.
Let t be the remaining time.
The standard distance equation is:
d = rt
We are given the rate as 2, so:
d = 2t
At the start of the walk, the remaining distance is 3 miles.
The remaining time is 1.5 hours.
At the end of the walk, the remaining distance is 0 miles.
The remaining time is 0 hours.
A graph of the distance and time would be a continuous, solid line. That's because the walker will be at every distance between 3 and 0 and every time between 1.5 and 0.
Answer:
The graph of this would be a solid line