Step-by-step explanation:
(2b-3)/(b-2)(b+2) = 3b(b-2)/(b+2)(b-2)
2b²+4b-3b-6/b²-4=3b²-6b/b²-4
2b²+b- 6= 3b²-6b
move square to square unknown to unknown
-b²+7b-6/b²-4
i also dk this is true or false
Answer:
24
Step-by-step explanation:
IDK
Answer:
B. 20
Step-by-step explanation:
<em>First, you divide by 5 from both sides of equation.</em>
<em>
</em>
<em>Simplify, to find the answer.</em>
<em>
</em>
<em>
, which is our answer.</em>
To check for continuity at the edges of each piece, you need to consider the limit as 
approaches the edges. For example,
has two pieces, 
and 
, both of which are continuous by themselves on the provided intervals. In order for 
to be continuous everywhere, we need to have
By definition of , we have 
, and the limits are
The limits match, so is continuous.
For the others: Each of the individual pieces of 
are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.
Answer:
Step-by-step explanation:
First we multiply x through (y+1). This equals xy +x.
Second we take 3 through (y+1). This equals 3y+3.
Next we take xy + x through (x+2). This equals 2x squared, y + 2x squared.
Fourth we take 3y+3 through (x+2). This equals 6xy + 6x.
