10. -1,-6
11. 1,6
12. 9
13. 6
14. 18
Answer: the value for the associated test statistic is 1.2653
Step-by-step explanation:
Given that;
sample size one n₁ = 10
mean one x"₁ = 6.4
standard deviation one S₁ = 1.1
sample size two n₁ = 11
mean two x"₂ = 5.6
standard deviation one S₁ = 1.7
H₀ : μ₁ = μ₂
H₁ : μ₁ ≠ μ₂
Pooled Variance
sp = √( { [(n₁ - 1) × s₁² + (n₂ - 1) × s₂²] / (n₁ + n₂ - 2)} × (1/n₁ + 1/n₂))
we substitute
= √( { [(10 - 1) × (1.1)² + (11 - 1) × (1.7)²] / (10 + 11 - 2)} × (1/10 + 1/11))
= √( { [(9) × 1.21 + (10) × 2.89] / (19) } × (0.1909))
= √({[ 39.79 ] / 19} × (0.1909))
= √( 2.0942 × 0.1909)
= √( 0.39978 )
= 0.63228
Now Test Statistics will be;
t = ( x"₁ - x"₂) / sp
we substitute
t = ( 6.4 - 5.6) / 0.63228
t = 0.8 / 0.63228
t = 1.2653
Therefore the value for the associated test statistic is 1.2653
The correct answer is that Hector placed Puppy 3 at -3.4 instead of at -0.75.
So A would be your correct answer. -3/4 is equivalent to -0.75. Think of it like money. 4 quarters equals $1.00. 3 quarters is 75 cents, or .75 which is this. Don’t forget the signs though. God bless you.
In probability, you study the chances of an event to happen based on statistics gathered. Probability is always expressed as a part of a whole, thereby in fractions or percentages. From the statistics gathered, it said that 80% of the time, the plane arrives right on schedule in El Centro. That means that the probability of NOT arriving on time is the other portion, which is 20%. Thus, the answer is 20%.
80 ...........................
