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Feliz [49]
2 years ago
12

The coordinates of three corners of a rectangle are A (2, 3), B (-5, 3), C (-5, -2).

Mathematics
1 answer:
Doss [256]2 years ago
3 0

Answer:

The answer to this is (2,-2)

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Write an equation that could be used to find the value of x using the interior angles of ∆BDC, then solve it.
Alecsey [184]

9514 1404 393

Answer:

  x = 16

Step-by-step explanation:

Either or both of the right triangles can be used to find x. Or, triangle ABC could be used. All numbers are assumed to be degrees.

<u>Using ∆ABD</u>

  55 +90 +2x+3 = 180

  2x = 32 . . . . . . subtract 148

  x = 16

<u>Using ∆BCD</u>

  50 +90 +2x+8 = 180

  2x = 32 . . . . . . subtract 148

  x = 16

<u>Using ∆ABC</u>

  55 +(2x +3) +50 +(2x +8) = 180

  4x = 64 . . . . . . . subtract 116

  x = 16

6 0
3 years ago
On a coordinate plane, 2 lines with negative slopes are shown. Line M N goes through points (negative 2, 0) and (negative 6, 8).
Ludmilka [50]

Answer:

Line MN was translated down  

✔ 4

units and right  

✔ 8

units to create line M'N'.

 The slope of Line M N  

✔ −2

. The slope of Line M prime N prime  

✔ −2

.

Step-by-step explanation:

On edge 2021 Hope this helps :)

7 0
2 years ago
Read 2 more answers
When grading an exam, 90% of a professor's 50 students passed. If the professor randomly selected 10 exams, what is the probabil
Damm [24]

Using the binomial distribution, it is found that there is a:

a) 0.9298 = 92.98% probability that at least 8 of them passed.

b) 0.0001 = 0.01% probability that fewer than 5 passed.

For each student, there are only two possible outcomes, either they passed, or they did not pass. The probability of a student passing is independent of any other student, hence, the binomial distribution is used to solve this question.

<h3>What is the binomial probability distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 90% of the students passed, hence p = 0.9.
  • The professor randomly selected 10 exams, hence n = 10.

Item a:

The probability is:

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{10,8}.(0.9)^{8}.(0.1)^{2} = 0.1937

P(X = 9) = C_{10,9}.(0.9)^{9}.(0.1)^{1} = 0.3874

P(X = 10) = C_{10,10}.(0.9)^{10}.(0.1)^{0} = 0.3487

Then:

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1937 + 0.3874 + 0.3487 = 0.9298

0.9298 = 92.98% probability that at least 8 of them passed.

Item b:

The probability is:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

Using the binomial formula, as in item a, to find each probability, then adding them, it is found that:

P(X < 5) = 0.0001

Hence:

0.0001 = 0.01% probability that fewer than 5 passed.

You can learn more about the the binomial distribution at brainly.com/question/24863377

3 0
2 years ago
Dan earns £384 over the course of a five-day week. How much is that per day?
Aneli [31]

Answer:76.8

Step-by-step explanation:divde by 7 hope this helps god bless

5 0
3 years ago
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What is 0.4 of 10? It’s percents
marusya05 [52]

Answer:

4%

Step-by-step explanation:

3 0
2 years ago
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