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trapecia [35]
3 years ago
12

Help needed asap please help!!!!!

Mathematics
2 answers:
shusha [124]3 years ago
7 0
It is the last one :)
Setler79 [48]3 years ago
4 0

Answer:

The bottom one

Step-by-step explanation:

Because they all are over five and you need a number that is under.

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The screen on Lin's cell phone allows for 8 lins of text per message. The maximum number of characters for each message is 10. H
julia-pushkina [17]
There will 80 characters per each line hold. Hope it help!
8 0
3 years ago
Urgent, I need help quickly
Alexeev081 [22]

Answeit is blurry for me take a picture again

Step-by-step explanation:

6 0
3 years ago
Kenny wants to learn how to serve overhand in volleyball. When he practiced yesterday, he made 7 serves over the net for every 2
Yakvenalex [24]

Answer: 28

Step-by-step explanation:

Given

Kenny made 7 serves over the net for every 2 serves that did not go over the net i.e. success rate of Kenny is

\Rightarrow \text{success rate}=\dfrac{7}{2+7}\times 100=\dfrac{700}{9}\%

for 36 serves, applying the same success rate, it is

\Rightarrow \text{success rate}=\dfrac{700}{9}\times\dfrac{1}{100}\times 36=28

Serves that did not make over the net is 36-28=8

Thus, Kenny will make 28 serves that make over the net

8 0
3 years ago
Hi can someone please help me with this i will give you five stars!!
tino4ka555 [31]

Step-by-step explanation:

Let's look at what we know. We know that...

P=2000

r=0.04 (Change 4% to a decimal)

t=7 (25 years minus 18 years equals 7)

n=1

Since we are compounding each year, we need to use this equation: P(1+\frac{r}{n} )^{nt}

Now just plug the numbers in: (Answer to #1:) 2000(1+\frac{0.04}{1} )^{(1*7)}

This equals 2631.86

When we round, this equals to $2,632. (Answer to #2).

3 0
2 years ago
The measurement of the height of 600 students of a college is normally distributed with a mean of
ioda

Answer:

68

Step-by-step explanation:

We let the random variable X denote the height of students of the college. Therefore, X is normally distributed with a mean of 175 cm and a standard deviation of 5 centimeters.

We are required to determine the percent of students who are between 170 centimeters and 180 centimeters in height.

This can be expressed as;

P(170<X<180)

This can be evaluated in Stat-Crunch using the following steps;

In stat crunch, click Stat then Calculators and select Normal

In the pop-up window that appears click Between

Input the value of the mean as 175 and that of the standard deviation as 5

Then input the values 170 and 180

click compute

Stat-Crunch returns a probability of approximately 68%

5 0
3 years ago
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