The third one is the correct graph for the equation
hope it helps !!
<span>5x^2 + 5y^2 + 10x − y = 0 it is the same of </span>
<span>x^2 + y^2 + 2x −1/5y = 0
and then </span>
(x + 1)^2 - 1+ (<span><span>y−1/10)^2 -1/100=0
</span> </span>(x + 1)^2 + (<span>y −1/10)^2 =(101/100)
the center is C(-1, 1/10), and the radius is R= sqrt(101)/10
</span>
Answer:
b=-2aH
Step-by-step explanation:
H=-b/2a
Apply cross multiplication
H×2a=-b
2aH=-b
In the question you are to find positive b not negative b so you have to take negative b to the left hand side of the equation to become positive b and take 2aH to the right hand side to become -2aH
therefore b=-2aH
Answer:
30 degrees
Step-by-step explanation:
the line (not at the 0) is what you measure from. Because the angle is visibly acute, we know that it must be less than 90 degrees, therefore the angle cannot be 150 degrees but 30 degrees (from the lower line)
F(x) = ax + b
maka..
f(1) = 3
a(1) + b = 3 --> a+b = 3
f(2) = 5
a(2) + b = 5 --> 2a+b = 5
untuk mencari nilai a dan b nya, di eliminasi, maka dapat
a=2 dan b=1
