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3 years ago

Someone plz help!! Also plz explain how you got that answer so I can do the rest!

Mathematics

1 answer:

zlopas [31]3 years ago

8 0

What is the question you are trying to answer? The question got cut off?

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Solve for y<br> 2x + 5y > 3y + 10

vladimir1956 [14]

Answer:

y>5-x

Step-by-step explanation:

To solve this problem we need start by grouping terms in the same side of inequality.

Lets begging by grouping 'y' terms on the left side of inequality sign, to do this, subtract 3y to both sides:

2x+5y-3y>3y-3y+10

2x+2y>10

Now lets subtract 2x to both sides of inequality.

2x-2x+2y>10-2x

2y>10-2x

Now isolate variable x by dividing the inequaiity by 2.

y>5-x

That is the solution

7 0

3 years ago

A/2 - 1/2 and please explain!!

Tema [17]

We need to know that:

$\frac{a}{b}-\frac{c}{d}=\frac{a.d-b.c}{b.d}$

$\frac{a}{2}-\frac{1}{2}=\frac{a.2-2.1}{2.2}=\frac{2a-2}{4}=\frac{a-1}{2}$

8 0

3 years ago

Write a fraction that is equivalent to 6 divided by 27

faust18 [17]

27/6 because this shows that you are dividing 6 from 27.

5 0

3 years ago

Read 2 more answers

Which coordinate grid shows Point A at (−0.25, 1.75)?

Levart [38]

Question:

Which coordinate grid shows Point A at (−0.25, 1.75)?

6 0

3 years ago

find all numbers such that a third of a number increased by half that number is at least 3 less than that same number

nirvana33 [79]

Answer:

All real numbers less than or equal to 18

Step-by-step explanation:

Let

x -----> the number

we know that

The algebraic expression that represent this situation is

$\frac{1}{3}x+\frac{1}{2}x \geq x-3$

Solve for x

Multiply by 6 both sides to remove the fractions

$2x+3x \geq6x-18$

Combine like terms left side

$5x \geq6x-18$

Adds 18 both sides

$5x+18 \geq 6x$

Subtract 5x both sides

$18 \geq 6x-5x$

$18 \geq x$

Rewrite

$x\leq 18$

All real numbers less than or equal to 18

6 0

3 years ago