Hey Rireneb!
This is a pretty simple Geometry question, so I will explain it in-depth for you to understand clearly! What you have displayed in the image is an isosceles triangle, meaning that both base angles are congruent (to each other). You know that the angle opposite to the base is 93.5, so you can subtract that from 180 and get 180-93.5=86.5
So, your base angles must be equal AND equal 86.5 when added up. So you must do the following, 86.5/2, which would get you to the answer 43.35. So, 43.25 is the value of each base angle, meaning that x = 43.25. Finally, the most appropriate answer to your question would be option 2!
Hope I was able to help! If you need any more help, please let me know and I will further assist you.
Answer:
3
Step-by-step explanation:
If the angle is greater than 360°, subtract 360° until the angle is less than 360°
Applying the formula for the area of a sector and length of an arc, the value of k is calculated as: 27.
<h3>What is the Area of a Sector?</h3>
Area of a sector of a circle = ∅/360 × πr²
<h3>What is the Length of an Arc?</h3>
Length of arc = ∅/360 × 2πr
Given the following:
- Radius (r) = 9 cm
- Length of arc = 6π cm
- Area of sector = kπ cm²
Find ∅ of the sector using the formula for length of acr:
∅/360 × 2πr = 6π
Plug in the value of r
∅/360 × 2π(9) = 6π
∅/360 × 18π = 6π
Divide both sides by 18π
∅/360 = 6π/18π
∅/360 = 1/3
Multiply both sides by 360
∅ = 1/3 × 360
∅ = 120°
Find the area of the sector:
Area = ∅/360 × πr² = 120/360 × π(9²)
Area = 1/3 × π81
Area = 27π
Therefore, the value of k is 27.
Learn more about area of sector on:
brainly.com/question/22972014
a=2 b=3 and c=4. then,
<em>a2+2abc+b2+c2</em>
<em>a2+2abc+b2+c2</em><em>=</em><em> </em><em>2</em><em>^</em><em>2</em><em>+</em><em>2</em><em>×</em><em>2</em><em>×</em><em>3</em><em>×</em><em>4</em><em>+</em><em>3</em><em>^</em><em>2</em><em>+</em><em>4</em><em>^</em><em>2</em>
<em>(</em><em>replace</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>a</em><em>,</em><em> </em><em>b</em><em>,</em><em> </em><em>c</em><em> </em><em>by</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em> </em><em>respectively</em><em> </em><em>tgen</em><em> </em><em>solve</em><em>)</em>
<em>=</em><em> </em><em>4</em><em>+</em><em>4</em><em>8</em><em>+</em><em>9</em><em>+</em><em>1</em><em>6</em>
<em>=</em><em> </em><em>7</em><em>7</em><em>…</em><em>…</em><em>…</em><em>…</em><em>…</em><em>…</em>
<em> </em><em>Therefore</em><em>,</em><em> </em><em>7</em><em>7</em><em> </em><em>is</em><em> </em><em>correct</em><em> </em><em>answer</em><em>.</em>
Step-by-step explanation:
making x subject in eq 1
x= (-1-9y)/-14
substituting the value of x in eq 2
17(-1-9y/-14)=7+9y
(-17-153y)/-14=7+9y
-17-153y=-98-126y
-17+98=153y-126y
81=27y
y=3
substituting this value of y in eq 1
-14x=-1-9(3)
-14x=-28
x=2
(x,y) = (2,3)
