F(x) = -3x2 – 20 Find f(-7) Evaluate the function Pls help

Can somebody do this budget form for me?

Rama09 [41]

Answer:8by-step explanation:

4 0

1 year ago

On a piece of paper, graph f(x) = [x if < 2 2 if x > 2 Then determine which answer

denis23 [38]

Answer:

below

Step-by-step explanation:

Step-by-step explanation:

The graph has two parts. There is one line for x < 2. It has a slope of 1 and a y-intercept of 0.

The line for x > 2 is the horizontal line x=2.

The point at x=2 is not defined by the function you have posted here, so there is a "hole" in the graph at that point.

7 0

2 years ago

Find the derivative of <img src="https://tex.z-dn.net/?f=%20y%20%3D%20%5Csqrt%5B3%5D%7Bx%7D%20" id="TexFormula1" title=" y =

MAXImum [283]

Answer:

$\displaystyle y'(27) = \frac{1}{27}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

y = ∛x

x = 27

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle y = x^{\frac{1}{3}}$
Basic Power Rule: $\displaystyle y' = \frac{1}{3}x^{\frac{1}{3} - 1}$
Simplify: $\displaystyle y' = \frac{1}{3}x^{-\frac{2}{3}}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{1}{3x^{\frac{2}{3}}}$

Step 3: Solve

Substitute in x [Derivative]: $\displaystyle y'(27) = \frac{1}{3(27)^{\frac{2}{3}}}$
Evaluate exponents: $\displaystyle y'(27) = \frac{1}{3(9)}$
Multiply: $\displaystyle y'(27) = \frac{1}{27}$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

8 0

2 years ago

Anybody Know This. ?

FinnZ [79.3K]

Answer:

No... i'm sorry

Step-by-step explanation:

4 0

2 years ago

Identify all rays and lines in the picture below. (Full question above)

Arte-miy333 [17]

Answer:

$\bold{Rays:}\ \overrightarrow{EA},\ \overrightarrow{EB},\ \overrightarrow{EC},\ \overrightarrow{ED},\ \overrightarrow{DE},\ \overrightarrow{BE}\\\\\bold{Lines:}\ \overleftrightarrow{ED},\ \overleftrightarrow{BE}$

Step-by-step explanation:

Look at the picture.

4 0

2 years ago