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melisa1 [442]
3 years ago
7

Pls help, i will be so grateful if you show work, pls

Mathematics
1 answer:
attashe74 [19]3 years ago
3 0

Answer:

Can you type out the question? it is hard to read and the angle makes it harder

Step-by-step explanation:

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Why i`m very weak in maths​
zmey [24]

Answer:

your slow

Step-by-step explanation:

5 0
2 years ago
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Find the value of x.<br> 1) m_2 = 3x + 13<br><br> y’all please help
natali 33 [55]

Answer:

x-- 3

Step-by-step explanation:

3 0
3 years ago
Trigonometry questions
trasher [3.6K]

We'll use standard labeling of right triangle ABC, C=90 degrees, legs a, b, hypotenuse c.

11.

Right triangle, cliff peak A, boat B, angle opposite cliff is B=28.9 deg. adjacent leg a=65.7 m, cliff height is leg b.

tan B = b/a

b = a tan B = 65.7 tan 28.9° = 36.3 m

12.

Similar story, boat at B, opposite b=3.5 m, rope c=12 m

sin B = b/c

B = arcsin b/c = arcsin (3.5/12) = 17.0°

13.

c=124 m, A=58°

sin A = a/c

a = c sin A = 124 sin 58 = 105.2 m

14.

That's a hypotenuse c=4-1.2 = 2.8 m to a height b=1.8m so

cos A = b/c

A = arccos b/c = arccos (1.8/2.8) = 50.0°

15.

Not a right triangle, an isosceles triangle.  Half of it is a right triangle with hypotenuse one arm, c=9.8 cm and angle opposite half the base of B=62/2=31°.  We're after d=2b:

sin B = b/c

b = c sin B

d = 2b = 2 c sin B = 2(9.8) sin 31 = 10.1 cm

Almost equilateral


4 0
3 years ago
Find the greatest common factor of 15x^2y^3 and -18x^3yz <br> The Answer has to be like _x_y_
Daniel [21]

Answer:

The greatest common factor of this would be 3x^2y

Step-by-step explanation:

In order to find this, first find the greatest common factor of the coefficients. Since 3 goes in evenly to both 15 and -18, then we know that it is a common factor.

From there we need to find the number of x's. Since the first term only has 2 x's and the second has 3, we take the lowest number. (x^2)

And since the first term has 3 y's and the second has just 1, we take the lowest number (y).

8 0
3 years ago
What is the formula for intersecting chords on the interior of a circle?​
Ratling [72]

Answer:

Each chord is cut into two segments at the point of where they intersect. One chord is cut into two line segments A and B. The other into the segments C and D. This theorem states that A×B is always equal to C×D no matter where the chords are.

4 0
2 years ago
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