All categories

3 years ago

Solve the inequality 6(x-3)/8≥3

Mathematics

1 answer:

vivado [14]3 years ago

8 0

Answer:

x≥7

Step-by-step explanation:

6(x-3)/8≥3

Multiply each side by 8/6

8/6*6(x-3)/8≥3*8/6

(x-3)≥4

Add 3 to each side

x-3+3≥4+3

x≥7

You might be interested in

The width of a rectangle is 8 units less than the length. If the area is 153 square units, then find the dimensions of the recta

Liono4ka [1.6K]

Length: 17 units
Width: 9 units. i think this is right

6 0

3 years ago

53° 78° x° find the value of x

Talja [164]

Answer:

I would say 49 is your answer

Step-by-step explanation:

53 plus 78 qould equal 131

subtract 131 from 180 and you get 49

add up all your numbers including x then they should all equal 180

4 0

3 years ago

PLEASE ANSWER ASAP REALLY EASY QUESTION WILL GET BRAINLEST!!!!!!!!!!!

-Dominant- [34]

Answer:

random since it doesn't have a specific opinion, it is required by bank service

Step-by-step explanation:

3 0

3 years ago

What are all of the real roots of the following polynomial? f(x) = x4 - 13x2 + 36

GREYUIT [131]

ANSWER

A. -3, -2, 2, and 3

EXPLANATION

The given polynomial function is,

$f(x) = {x}^{4} - 13 {x}^{2} + 36$

To find the real roots, we equate the function to zero to obtain;

${x}^{4} - 13 {x}^{2} + 36 = 0$

We can solve this equation as a quadratic equation in
${x}^{2}.$

Thus we rewrite the equation as,

$({x}^{2})^{2} - 13 {x}^{2} + 36 = 0$

We split the middle term to get,

$({x}^{2})^{2} - 9 {x}^{2} - 4 {x}^{2} + 36 = 0.$

We factor to get,

${x}^{2} ( {x}^{2} - 9) - 4( {x}^{2} - 9) = 0$

We factor to get,

$( {x}^{2} - 9)( {x}^{2} - 4) = 0$

Either

${x}^{2} - 9 = 0$
or

${x}^{2} - 4 = 0$

$x = \pm \sqrt{9} \: or \: x = \pm \sqrt{4}$
$x = \pm3 \: or \: x = \pm2$

$x=-3,-2,2,3$

The correct answer is A

5 0

3 years ago

Read 2 more answers

Linear or non-linear?

Gnoma [55]

Answer:

the answer for this question is non-linear

Step-by-step explanation:

linear means in a straight line. the question you wrote is NOT in a strait line.

hoped the answer helped

7 0

3 years ago