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son4ous [18]
3 years ago
11

The perimeter of a triangle with two equal sides is 50 cm. If its base were lengthened by 3 cm and each leg were shortened by 4

cm, all three sides would be equal. Find the length of the base of the original triangle.
Mathematics
1 answer:
Nataly [62]3 years ago
6 0

Answer:

Base of the original triangle is 12 cm.

Step-by-step explanation:

Let base of triangle be x  

two equal legs  of triangles by y

therefore perimeter of triangle

                       x+y+y = 50 or x+2y =50

according to the question

 if base is x+3 and leg is y-4

then both are equal

   that is x+3 = y-4

            y-x = 7 or y =x+7

   x+2y =50

   x+2(x+7) = 50

    x+2x +14 =50

     3x +14 =50

     3x = 50 -14

      3x = 36

      x = 12

therefore base of the original  triangle is 12 cm                    

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Answer:

There was no error

Step-by-step explanation:

There are two types of statistical errors, the type 1 error and the type 2 error. In this case we refute the null hypothesis when the hypothesis is, in fact, false, because the mean process is 9 days instead of 7. Therefore we made no errors.

If the null hypothesis were True, a type 1 error would have ocurred. If the null hypothesis were false and we didnt refute it, then a type 2 error would have ocurred.

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A study of pollutants showed that certain industrial emissions should not exceed 2.3 parts per million. You believe a particular
Musya8 [376]

Answer:

t=\frac{3.3-2.3}{\frac{0.4}{\sqrt{9}}}=7.5    

The degrees of freedom are given by:

df=n-1=9-1=8  

And the p value would be:

p_v =P(t_{(8)}>7.5)=0.0000346  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 2.3 ppm the safe limit

Step-by-step explanation:

Information provided

\bar X=3.3 represent the sample mean in ppm

s=0.4 represent the sample standard deviation

n=9 sample size  

\mu_o =2.3 represent the value to verify

\alpha=0.05 represent the significance level

t would represent the statistic  

p_v represent the p value

System of hypothesis

We want to verify if the true mean is higher than 2,3 ppm, the system of hypothesis would be:  

Null hypothesis:\mu \leq 2.3  

Alternative hypothesis:\mu > 2.3  

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{3.3-2.3}{\frac{0.4}{\sqrt{9}}}=7.5    

The degrees of freedom are given by:

df=n-1=9-1=8  

And the p value would be:

p_v =P(t_{(8)}>7.5)=0.0000346  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 2.3 ppm the safe limit

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You'd likely find this problem easier if you'd write these two numbers on separate lines, one above the other:

1015
+119
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scoundrel [369]

Answer:

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Step-by-step explanation:

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