The perimeter of a triangle with two equal sides is 50 cm. If its base were lengthened by 3 cm and each leg were shortened by 4
cm, all three sides would be equal. Find the length of the base of the original triangle.
1 answer:
Answer:
Base of the original triangle is 12 cm.
Step-by-step explanation:
Let base of triangle be x
two equal legs of triangles by y
therefore perimeter of triangle
x+y+y = 50 or x+2y =50
according to the question
if base is x+3 and leg is y-4
then both are equal
that is x+3 = y-4
y-x = 7 or y =x+7
x+2y =50
x+2(x+7) = 50
x+2x +14 =50
3x +14 =50
3x = 50 -14
3x = 36
x = 12
therefore base of the original triangle is 12 cm
You might be interested in
I hope this helps you
4.1+4. (-x)+2x=3.x+3.1
4-4x+2x=3x+3
-2x-3x=3-4
-5x= -1
x=1/5
A is your answer tell me if I am wrong.
A1 = 4
a2 = 5a1 = 5 x 4 = 20
a3 = 5a2 = 5 x 20 = 100
a4 = 5a3 = 5 x 100 = 500
a5 = 5a4 = 5 x 500 = 2,500
Tn = ar^(n-1); where a = 4, r = 5
Tn = 4(5)^(n-1) = 4/5 (5)^n
Explicit formular is Tn = 4/5 (5)^n
Recursive formular is
-3/5x + 1/5 > 7/20
-3/5x > 7/20 - 1/5
-3/5x > 7/20 - 4/20
-3/5x > 3/20
x < 3/20 * - 5/3
x < -15/60 reduces to -1/4