Let length, width, and height be s.
Then diagonal of any face would be √( s² + s² ) = √( 2s² )
And we know that it measures √( 500 ) so that's sufficient for us to figure out the length of an edge of the cube. We do not need to worry about the diagonal of the cube.
Now we have to solve √( 500 ) = √( 2s² )
Square both sides:
500 = 2s²
Divide both sides by 2:
250 = s²
Take the square root of both sides:
√(250) = s ≈ 15.8113883
Rounding to nearest tenth:
s ≈ 15.8
Final answer: 15.8
Hope this helps.
If we draw the contingency table of x (vertical) against y (horiz.), we have a square.
For n=4, we have (legend: < : x<y = : x=y > : x>y
y 1 2 3 4
x
1 = < < <
2 > = < <
3 > > = <
4 > > > =
We see that there are n(n-1)/2 cases of x<y out of n^2.
Therefore,
p(x<y)=n(n-1)/(2n^2)=(n-1)/(2n)
However, if the sample space is continuous, it will be simply p(x<y)=1/2.
we can use synthetic division
and then we can find quotient
we can see in the image
we will get
so, we get
.............Answer
Answer:
-1280
Step-by-step explanation:
There are 2 ways you could do this. You could just do the question until you come to the end of f(4). That is likely the simplest way to do it.
f(1) = 160
f(2) = - 2 * f(1)
f(2) = -2*160
f(2) = -320
f(3) = -2 * f(2)
f(3) = -2 * - 320
f(3) = 640
f(4) = - 2 * f(3)
f(4) = - 2 * 640
f(4) = - 1280
I don't know that you could do this explicitly with any real confidence.
