Which second degree polynomial function f(x) has a lead coefficient of 3 and roots 4 and 1?
2 answers:
For this case we have that the following function complies with the given conditions:
To prove it, let's find the roots of the polynomial:
By doing common factor 3 we have:
Factoring the second degree polynomial we have:
Then, the solutions are:
Solution 1:
Solution 2:
Answer:
A second degree polynomial function f (x) that has a lead coefficient of 3 and roots 4 and 1 is:
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Answer:
Step-by-step explanation:
Given the center of sphere is: (-2, 2, 3)
Passes through the origin i.e. (0, 0, 0)
To find:
The equation of the sphere ?
Solution:
First of all, let us have a look at the equation of a sphere:
Where () are the points on sphere.
is the center of the sphere and
is the radius of the sphere.
Radius of the sphere is nothing but the distance between any point on the sphere and the center.
We are given both the points, so we can use distance formula to find the radius of the given sphere:
Here,
So, Radius is:
Therefore the equation of the sphere is:
1) Since we have the slope, and one point we can find that linear equation using this point-slope formula. Plugging them we have:
2) Note that we had to add 1 to both sides, to keep the "y "on the left.
3) Therefore, y=-9x+10 is the answer.