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Aloiza [94]
3 years ago
6

PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ HELP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE I BEGGING YOUPLZ

HELP plz show your work GOD STOP SKIPING AND TROLLING MY QUESTION PLZZZZZZZZ 7TH GRADE WORK
1. 1/4 ÷ 2 1/4

2. Solve and graph the solution to each inequality below.
2(3y-2)>8


4. Solve and graph the solution to the inequality below.
4x+24≤ 32

5. Solve and graph the solution to the inequality below. 5n+5>-45
Mathematics
1 answer:
ohaa [14]3 years ago
6 0

Answer:

1 one is 9, 2nd is -2

Step-by-step explanation:

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Can someone please help my ASAP
Inga [223]

Domain: (-∞, ∞)

Range: (-∞,1]

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3 years ago
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The price of technology stock has risen $9.87 today yesterday's price is $9.74 find the percentage increase round your answer to
Kitty [74]

Step-by-step explanation:

To find the percent increase, divide the increase by the original price.

P1 = price yesterday

P2 = price today

To find percent increase

\frac{(p2 - p1)}{p1}

Or to answer the question,

P1 = 9.74

P2 = 9.87

\frac{(9.87 - 9.74)}{9.74}  = 0.013347

Or 1.33%

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3 years ago
Ellie purchased 7 shirts that were originally priced at $15.50
notka56 [123]

Answer:

10.85

Step-by-step explanation:

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What is the solution to 2(x - 6) = 14?
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Answer:

Step-by-step explanation:

2x-12=14

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3 years ago
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Two dice are rolled. Let the random variable X denote the number that falls uppermost on the first die and let Y denote the numb
Vlada [557]

Step-by-step explanation:

a) Lets start by giving the answer:

The probability distribution of X is:

P(X=x)=\frac{1}{6}

For every x = 1, 2, 3, 4, 5, 6

Same for Y:

P(Y=y)=\frac{1}{6}

For every y = 1, 2, 3, 4, 5, 6

This is because each variable has 6 possibilities which are equiprobable. In other words, every number (1 to 6) has the same probability of falling uppermost on each dice.

Now if the question refers to a joint probability distribution, then we have a joint random viariable (X,Y). This probability is given by:

P[(X,Y)=(x,y)] = \frac{1}{36}

For every x = 1, 2, 3, 4, 5, 6 and y = 1, 2, 3, 4, 5, 6

The reason for this is that the combination of the result of both dices produces 36 equiprobable possibilities.

b) For the probability distribution of the sum of the variables we may define:

Z=X+Y

The for the random variable Z the next results are possible:

Z       P(Z)

2       1/36

3       2/36

4       3/36

5       4/36

6       5/36

7       6/36

8       5/36

9       4/36

10      3/36

11       2/36

12      1/36

This is our probability distribution for the sum of X+Y. Now to understand the results lets see some examples:

For z = 2 (x=1 and y=1) we obtain the probability P(Z=2)=\frac{1}{36}, this is because we have 1 possibility to obtain (1,1) among 36 possibilities.

For z = 4 that is for (x=1, y=3) and (x=2, y=2) and (x=3, y=1) we obtain P(Z=4)=\frac{3}{36} this is because we have 3 possibilities to obtain any of the combinations mentioned among 36 possibilities.

For z = 10 that is for (x=4, y=6) and (x=5, y=5) and (x=6, y=6) we obtain P(Z=4)=\frac{3}{36} because we have 3 possibilities to obtain any of the combinations mentioned among 36 possibilities.

8 0
4 years ago
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