Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
Answer:
5.1 and 5.05
Not really much to explain. Still, hope this helped!
P.S. (5.2 is more than 5.03, btw)
Hi there!
In order to use the elimination method, you have to create one variable that has the same coefficient. This is to be able to eliminate one variable and have a one variable equation (which you can then solve).
In your case, we'll have the "x" have the same coefficient by multiplying the top equation by 4 and the bottom equation by 2 :
4( -2x + 3y = -4) → -8x + 12y = -16
2( 4x - 2y = 16) → 8x - 4y = 32
Now that both of your equation have a variable with the same coefficient, you need to choose rather you need to add or subtract the equations in order to get rid of the variable (in this case we want to get rid of the "x").
In your case, you want to add both equation together which will give you :
8y = 16
Now that you only have one variable, all you need to do now is solve the equation for "y" :
8y = 16
Divide each side of the equation by 8
y = 2 → Your answer
There you go! I really hope this helped, if there's anything just let me know! :)
Answer:
Yes
Step-by-step explanation:
0.99
Hope this helps
Mark brainliest please
