The form of promotion that would work for technical products like automobiles is b. Informative promotion.
<h3>What is informative promotion?</h3>
This is where features of the good being advertised are elaborated on to ensure the viewer understands the product's functionality.
This is useful for technical products like computers and cars as there is a need for customers to know what makes them better.
Options for this question include:
a. Persuasive promotion
b. Informative promotion
c. Connective promotion
d. Reminder promotion
Find out more on types of promotion at brainly.com/question/11131986
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Answer:
Spotlighter, Inc.
Cash
Account Titles Debit Credit
Beginning balance $0
Notes Payable $4,740
Common stock $5,430
Equipment $1,000
Supplies $1,100
Ending balance $8,070
Notes Payable
Account Titles Debit Credit
Beginning balance $0
Cash $4,740
Equipment 1,600
Ending balance $6,340
Common stock
Account Titles Debit Credit
Beginning balance $0
Cash $5,430
Equipment
Account Titles Debit Credit
Beginning balance $0
Cash $1,000
Notes Payable $1,600
Ending balance $2,600
Supplies
Account Titles Debit Credit
Beginning balance $0
Cash $1,100
Accounts Payable $1,500
Ending balance $2,600
Accounts Payable
Account Titles Debit Credit
Beginning balance $0
Supplies $1,500
Ending Balance $1,500
Explanation:
1) Data and Transaction Analysis:
a. Cash $4,740 Notes Payable $4,740
b. Cash $5,430 Common stock $5,430
c. Equipment $2,600 Cash $1,000 Notes Payable $1,600
d. Supplies $1,100 Cash $1,100
e. Supplies $1,500 Accounts Payable $1,500
Answer:
what is this i don't know hope I will understand plz don't be angry
Home goods has things like that or world market
For compounding interest, there is a formula relating the present worth (P) with the annuity (A). This is shown in the picture. The 'i' is the effective interest rate while n is the time. You should make sure that you are consistent with the units. If your time is in terms of years, your interest should be in terms of percent per year compounded yearly. Moreover, your annuity should be per yearly basis. In this case, it is already consistent so we don't need to convert. Substituting the values,
P = 10,000[(1.08^9-1)/(0.08*1.08^9)]
P = $62,468.88
