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Karolina [17]
3 years ago
10

Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answ

er in the box provided to submit your solution.
(-8, 0) and (1, 5)
Mathematics
1 answer:
katen-ka-za [31]3 years ago
7 0

The equation of line through the given points is:

y=\frac{5}{9}x+\frac{40}{9}

Step-by-step explanation:

Given points are:

(-8,0) = (x1,y1)

(1,5) = (x2,y2)

The slope-intercept form of line is:

y=mx+b

We have to find the slope first

m=\frac{y_2-y_1}{x_2-x_1}\\m= \frac{5-0}{1-(-8)}\\m=\frac{5}{1+8}\\m=\frac{5}{9}

Putting the value of slope

y=\frac{5}{9}x+b

To find the value of y-intercept, we'll put the point (1,5) in the equation

5=\frac{5}{9}(1)+b\\5=\frac{5}{9}+b\\b=5-\frac{5}{9}\\b=\frac{45-5}{9}\\b=\frac{40}{9}

Putting the values of b and m in the equation

y=\frac{5}{9}x+\frac{40}{9}

The equation of line through the given points is:

y=\frac{5}{9}x+\frac{40}{9}

Keywords: Equation of line, slope-intercept form

Learn more about equation of line at:

  • brainly.com/question/4793866
  • brainly.com/question/4824362

#learnwithBrainly

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The area if a rectangle is 53.6cm^2.If the length is multiplied by four and the width is halved, the area would then be?
e-lub [12.9K]

Answer:

26.8cm²

Step-by-step explanation:

the area if a rectangle is 53.6cm^2.If the length is multiplied by four and the width is halved, the area would then be?​

Area of rectangle = length x width

53.6 = 4L x 1/2 W

53.6 = 2L × W

Divide both sides by 2

L × W = 53.6 ÷ 2

New area  = 26.8cm²

I hope this was helpful, please mark as brainliest

5 0
4 years ago
What would be the equation for this and the answer
atroni [7]

Answer:

The answer is k=61-26

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4 0
3 years ago
Read 2 more answers
Suppose a football is kicked with an initial velocity of 82 ft/sec., at an angle of
satela [25.4K]

Answer:

The position P is:

P = 87\^x + 75\^y ft     <u><em> Remember that the position is a vector. Observe the attached image</em></u>

Step-by-step explanation:

The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity s_0 is:

y(t) = y_0 + s_0t -16t ^ 2

Where y_0 is the initial height = 0 for this case

We know that the initial velocity is:

82 ft/sec at an angle of 58 ° with respect to the ground.

So:

s_0 = 82sin(58\°) ft/sec

s_0 = 69.54 ft/sec

Thus

y(t) = 69.54t -16t ^ 2

The height after 2 sec is:

y(2) = 69.54 (2) -16 (2) ^ 2

y(2) = 75\ ft

Then the equation that describes the horizontal position of the ball is

X(t) = X_0 + s_0t

Where

X_ 0 = 0 for this case

s_0 = 82cos(58\°) ft / sec

s_0 = 43.45 ft/sec

So

X(t) = 43.45t

After 2 seconds the horizontal distance reached by the ball is:

X (2) = 43.45(2)\\\\X (2) = 87\ ft

Finally the vector position P is:

P = 87\^x + 75\^y ft

6 0
3 years ago
What is 2(c+7)=2c+14
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2(c+7)=2c+14

Use distributive property

2*c +2*7

2c+14=2c+14

Hope it helps!

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