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3 years ago

Can some one help me

Mathematics

1 answer:

lara [203]3 years ago

5 0

Answer:

there nothing to solve

Step-by-step explanation:

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6(1) = 16<br> 6(n) = b(n − 1) + 1<br> Find the 2-term in the sequence.

Tresset [83]

Answer:

Step-by-step explanation:

Given

$b(1)=16\\ \\b(n)=b(n-1)+1$

Finding the second term of the sequence means to find $b(2).$ To find $b(2)$ substitute $n=2$ into the second expression:

$b(2)=b(2-1)+1\\ \\b(2)=b(1)+1\\ \\b(2)=16+1\\ \\b(2)=17$

6 0

3 years ago

How would you do this last part?

alina1380 [7]

Answer:

broken heart thats the last one lol

Step-by-step explanation:

8 0

3 years ago

You already owed your friend $5. This morning, you borrowed $4 more, and this afternoon you paid back $3. How much money do you

prisoha [69]

$6 ? 5+4 =9
9-3 =6

I don't know if this is correct but this is how I would do it

6 0

3 years ago

Read 2 more answers

Solving separable differential equation DY over DX equals xy+3x-y-3/xy-2x+4y-8

Ivanshal [37]

It looks like the differential equation is

$\dfrac{dy}{dx} = \dfrac{xy + 3x - y - 3}{xy - 2x + 4y - 8}$

Factorize the right side by grouping.

$xy + 3x - y - 3 = x (y + 3) - (y + 3) = (x - 1) (y + 3)$

$xy - 2x + 4y - 8 = x (y - 2) + 4 (y - 2) = (x + 4) (y - 2)$

Now we can separate variables as

$\dfrac{dy}{dx} = \dfrac{(x-1)(y+3)}{(x+4)(y-2)} \implies \dfrac{y-2}{y+3} \, dy = \dfrac{x-1}{x+4} \, dx$

Integrate both sides.

$\displaystyle \int \frac{y-2}{y+3} \, dy = \int \frac{x-1}{x+4} \, dx$

$\displaystyle \int \left(1 - \frac5{y+3}\right) \, dy = \int \left(1 - \frac5{x + 4}\right) \, dx$

$\implies \boxed{y - 5 \ln|y + 3| = x - 5 \ln|x + 4| + C}$

You could go on to solve for $y$ explicitly as a function of $x$ , but that involves a special function called the "product logarithm" or "Lambert W" function, which is probably beyond your scope.

8 0

2 years ago

The table shows the cost for ordering a certain number of tacos what is the values of x if the cost is proportional to the numbe

Lisa [10]

The answer is going to be $6.50. hope that helped

6 0

3 years ago