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2 years ago

Plzz help me with this question

Mathematics

1 answer:

Aleks04 [339]2 years ago

6 0

Answer: 45

Step-by-step explanation:

Complemntary angles result in a sum of 90. So, H=45 means

45+J=90

90-45= 45

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What congruence rule does the triangle follow? Please write the congruence statement triangle EFH is congruent to ________?

Yuliya22 [10]

We can see here two triangles, and we can notice the following:

1. Since H is the midpoint of the segment EG, we can say that EH and HG are congruent segments.

2. Since these two triangles, namely, EFH and GFH share the same segment (HF), this side is also congruent to these two triangles.

3. Since EH is congruent to HG, and FH is congruent to itself, then EF is congruent to GF.

4. Angle E is congruent to angle G.

Therefore, we can say that:

Since we have that:

a. EF is congruent to GF

b. EH is congruent to GH

c. Angle E is congruent to angle G

We can conclude that the congruence rule, in this case, is SAS (Side-Angle-Side), because<em> if two sides and the included angle are congruent to the corresponding parts of the other triangle, the triangles are congruent.</em>

<em>We also see that the three sides are congruent (and in this case, we can also conclude that the triangles are congruent by the rule SSS (side-side-side).</em>

Likewise, we can also conclude that the triangle EFH is congruent to triangle GFH.

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1 year ago

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Answer: 52/100 thank my beautiful sister for the answer

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3 years ago

y′′ −y = 0, x0 = 0 Seek power series solutions of the given differential equation about the given point x 0; find the recurrence

sukhopar [10]

Let

$\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = a_0 + a_1x + a_2x^2 + \cdots$

Differentiating twice gives

$\displaystyle y'(x) = \sum_{n=1}^\infty na_nx^{n-1} = \sum_{n=0}^\infty (n+1) a_{n+1} x^n = a_1 + 2a_2x + 3a_3x^2 + \cdots$

$\displaystyle y''(x) = \sum_{n=2}^\infty n (n-1) a_nx^{n-2} = \sum_{n=0}^\infty (n+2) (n+1) a_{n+2} x^n$

When x = 0, we observe that y(0) = a₀ and y'(0) = a₁ can act as initial conditions.

Substitute these into the given differential equation:

$\displaystyle \sum_{n=0}^\infty (n+2)(n+1) a_{n+2} x^n - \sum_{n=0}^\infty a_nx^n = 0$

$\displaystyle \sum_{n=0}^\infty \bigg((n+2)(n+1) a_{n+2} - a_n\bigg) x^n = 0$

Then the coefficients in the power series solution are governed by the recurrence relation,

$\begin{cases}a_0 = y(0) \\ a_1 = y'(0) \\\\ a_{n+2} = \dfrac{a_n}{(n+2)(n+1)} & \text{for }n\ge0\end{cases}$

Since the n-th coefficient depends on the (n - 2)-th coefficient, we split n into two cases.

• If n is even, then n = 2k for some integer k ≥ 0. Then

$k=0 \implies n=0 \implies a_0 = a_0$

$k=1 \implies n=2 \implies a_2 = \dfrac{a_0}{2\cdot1}$

$k=2 \implies n=4 \implies a_4 = \dfrac{a_2}{4\cdot3} = \dfrac{a_0}{4\cdot3\cdot2\cdot1}$

$k=3 \implies n=6 \implies a_6 = \dfrac{a_4}{6\cdot5} = \dfrac{a_0}{6\cdot5\cdot4\cdot3\cdot2\cdot1}$

It should be easy enough to see that

$a_{n=2k} = \dfrac{a_0}{(2k)!}$

• If n is odd, then n = 2k + 1 for some k ≥ 0. Then

$k = 0 \implies n=1 \implies a_1 = a_1$

$k = 1 \implies n=3 \implies a_3 = \dfrac{a_1}{3\cdot2}$

$k = 2 \implies n=5 \implies a_5 = \dfrac{a_3}{5\cdot4} = \dfrac{a_1}{5\cdot4\cdot3\cdot2}$

$k=3 \implies n=7 \implies a_7=\dfrac{a_5}{7\cdot6} = \dfrac{a_1}{7\cdot6\cdot5\cdot4\cdot3\cdot2}$

so that

$a_{n=2k+1} = \dfrac{a_1}{(2k+1)!}$

So, the overall series solution is

$\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = \sum_{k=0}^\infty \left(a_{2k}x^{2k} + a_{2k+1}x^{2k+1}\right)$

$\boxed{\displaystyle y(x) = a_0 \sum_{k=0}^\infty \frac{x^{2k}}{(2k)!} + a_1 \sum_{k=0}^\infty \frac{x^{2k+1}}{(2k+1)!}}$

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2 years ago

Rachel runs 3.2 miles each weekday and 1.5 miles each day of the weekend how many miles will she have run in six weeks

elena-14-01-66 [18.8K]

3.2 x 5 + 1.5 x 2 = 19

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3 years ago

The quotient of a number and -7 decreased by 2 is 10 find the number

yarga [219]

X/-7 -2 =10
x/-7 = 12
x = -84

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2 years ago

Plzz help me with this question​

Plzz help me with this question