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lisabon 2012 [21]
3 years ago
5

ANSWER PLEASE! 10 POINTS!! Dad says to pick a number from 1 to 100, and the

Mathematics
1 answer:
Kay [80]3 years ago
7 0
Answer: 52/100 thank my beautiful sister for the answer
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A saleswomen sells a dried fruit mixture for $5.7 per pound and nuts for $14.55 per pound. She wants to blend the two to get a 1
katen-ka-za [31]
Let the fruit mixture of $5.7 per pound be for x pounds.

The nut of $14.55 per pound would then be:   (10 -x).

Since the total blend of both = 10 pounds, selling for $9.24 per pound.

cost of 1st type + cost of second type = Total cost of blend mixture

5.7*x  +    14.55*(10 - x) = 9.24*10

5.7x + 145.5 - 14.55x = 92.4

5.7x - 14.55x = 92.4 - 145.5

-8.85x = -53.1

x =  -53.1/-8.85

x = 6

The other  will be (10 -x) = 10 - 6 = 4.  

She should use 6 lb of fruit mixture and 4 lb of nuts. 
6 0
4 years ago
If I have a triangle with a leg of 4 and a leg of 3 what is the length of the hypotenuse
Dmitrij [34]

Answer:

5

Step-by-step explanation:

To solve for hypotenuse we use the Pythagorean theorem:

a^2+b^2=c^2

In this theorem:

c= hypotenuse

a = leg

b = leg

Substitute into theorem:

4^2+3^2=c^2

16+9=c^2

25=c^2

(square root both sides)

5=c

Therefore the hypotenuse has a length of 5.

Please say thanks if correct :)

4 0
4 years ago
What is the value of x?
OlgaM077 [116]

Answer:

I honestly have no clue.

Step-by-step explanation:

I honestly have no clue.

6 0
3 years ago
What is the common difference of the arithmetic sequence:-4.6,-5.2,-5.8,-6.4
LenaWriter [7]

Answer: -0.6


Step-by-step explanation:

Common difference is obtained by taking  difference  of two consecutive.

  -5.2-(-4.6)

= -5.2+4.6

= -0.6

7 0
3 years ago
Approximately 13.2% of US drivers are younger than age 25, with 37.7% in the 25-44 age group, and 49.1% in the 45-and-over-categ
Elan Coil [88]

Answer:

could not be the same

Step-by-step explanation:

Given that approximately US drivers are agewise as follows:

<25   13.2

25-45   37.7%

>45   49.1%

Observations are made for a sample of 200 fatal accidents.

Let us create hypotheses as

H_0:  Proportions age wise are the same as for US drivers\\H_a: Proportions are different

(Two tailed chi square test at 5% significance level)

Age <25 25-45 >45  

Expected 13.2 37.7 49.1 100

Observed 42 80 78 200

Expected no  26.4 75.4 98.2 200

Chi square 9.218181818 0.280636605 4.155193483 13.65401191

df = 2

p value = 0.001084

Since p <0.05 we reject null hypothesis

At the  0.05 level, the age distribution of drivers involved in fatal accidents within the state could not be the same as the age distribution of all US drivers as there seems to be significant difference.

5 0
3 years ago
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