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S_A_V [24]
3 years ago
9

Write in function notation y=5x 3

Mathematics
2 answers:
Hoochie [10]3 years ago
5 0
The answer to the question is y=15
rjkz [21]3 years ago
3 0
The answer is x=15........
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−3 2/7−(−5/7) plz help me
balu736 [363]

Answer:

-2 or -14/7 (they're the same)

Step-by-step explanation:

  1. Write it out: -3\frac{2}{7} - (-\frac{5}{7})  
  2. Simplify. It should now look like this: -3\frac{2}{7} + \frac{5}{7}  
  3. Turn -3 2/7 into an improper fraction. It should now look like this: -19/7
  4. Add: -\frac{19}{7} + \frac{5}{7} = -\frac{14}{7} = -2  

I hope this helps!

3 0
3 years ago
Read 2 more answers
1-5.
Irina18 [472]
Can you possibly upload a picture?
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4 0
1 year ago
Solve the inequality. Graph the solution.<br><br> w+6≤−3
yuradex [85]

Answer: w<-9 With the line underneath

Step-by-step explanation:

4 0
3 years ago
Given m||n, find the value of x.<br> t<br> &gt;m<br> (x+14)<br> (9x-8)"
UkoKoshka [18]

Answer:

1st one

Step-by-step explanation:

8 0
3 years ago
What is the quadratic regression equation for the data set? ​ ​ ​ <br><br> PLEASEE HELP ME
Soloha48 [4]
You're trying to find constants a_0,a_1,a_2 such that \hat y=a_0+a_1\hat x+a_2{\hat x}^2. Equivalently, you're looking for the least-square solution to the following matrix equation.


\underbrace{\begin{bmatrix}1&6&6^2\\1&3&3^2\\\vdots&\vdots&\vdots\\1&9&9^2\end{bmatrix}}_{\mathbf A}\underbrace{\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}}_{\mathbf x}=\underbrace{\begin{bmatrix}100\\110\\\vdots\\70\end{bmatrix}}_{\mathbf b}

To solve \mathbf{Ax}=\mathbf b, multiply both sides by the transpose of \mathbf A, which introduces an invertible square matrix on the LHS.

\mathbf{Ax}=\mathbf b\implies\mathbf A^\top\mathbf{Ax}=\mathbf A^\top\mathbf b\implies\mathbf x=(\mathbf A^\top\mathbf A)^{-1}\mathbf A^\top\mathbf b

Computing this, you'd find that

\mathbf x=\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}\approx\begin{bmatrix}121.119\\-3.786\\-0.175\end{bmatrix}

which means the first choice is correct.
8 0
3 years ago
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