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Inga [223]
3 years ago
11

Nicole had already run 17 miles on her own and expects to run 1 mile during each track practice. How many miles would nicole hav

e run after 2( track practices?
Mathematics
1 answer:
Volgvan3 years ago
5 0
Answer: 19 mile

Explanation:

Each track practice = 1 mile

And she had run 17 miles on her own.

After 2 track practices she would have run 17 mile + 2 mile = 19 mile
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What is the measurement of the longest line segment in a right rectangular prism that is 26 inches long, 2 inches wide, and 2 in
EastWind [94]

Answer:

6\sqrt{19} \approx 26.153 inches.

Step-by-step explanation:

The longest line segment in a right rectangular prism is the diagonal that connects two opposite vertices. On the first diagram attached, the green line segment connecting A and G is one such diagonals. The goal is to find the length of segment \mathsf{AG}.

In this diagram (not to scale,) \mathsf{AB} = 26 (length of prism,) \mathsf{AC} = 2 (width of prism,) \mathsf{AE} = 2 (height of prism.)

Pythagorean Theorem can help find the length of \mathsf{AG}, one of the longest line segments in this prism. However, note that this theorem is intended for right triangles in 2D, not the diagonal in a 3D prism. The workaround is to simply apply this theorem on two different right triangles.

Start by finding the length of line segment \mathsf{AD}. That's the black dotted line in the diagram. In right triangle \triangle\mathsf{ABD} (second diagram,)

  • Segment \mathsf{AD} is the hypotenuse.
  • One of the legs of \triangle\mathsf{ABD} is \mathsf{AB}. The length of \mathsf{AB} is 26, same as the length of this prism.
  • Segment \mathsf{BD} is the other leg of this triangle. The length of \mathsf{BD} is 2, same as the width of this prism.

Apply the Pythagorean Theorem to right triangle \triangle\mathsf{ABD} to find the length of \mathsf{AB}, the hypotenuse of this triangle:

\mathsf{AD} = \sqrt{\mathsf{AB}^2 + \mathsf{BD}^2} = \sqrt{26^2 + 2^2}.

Consider right triangle \triangle \mathsf{ADG} (third diagram.) In this triangle,

  • Segment \mathsf{AG} is the hypotenuse, while
  • \mathsf{AD} and \mathsf{DG} are the two legs.

\mathsf{AD} = \sqrt{26^2 + 2^2}. The length of segment \mathsf{DG} is the same as the height of the rectangular prism, 2 (inches.) Apply the Pythagorean Theorem to right triangle \triangle \mathsf{ADG} to find the length of the hypotenuse \mathsf{AG}:

\begin{aligned}\mathsf{AG} &= \sqrt{\mathsf{AD}^2 + \mathsf{GD}^2} \\ &= \sqrt{\left(\sqrt{26^2 + 2^2}\right)^2 + 2^2}\\ &= \sqrt{\left(26^2 + 2^2\right) + 2^2} \\&= 6\sqrt{19} \\&\approx 26.153\end{aligned}.

Hence, the length of the longest line segment in this prism is 6\sqrt{19} \approx 26.153 inches.

5 0
3 years ago
There are 4 red balls, 6 white balls, and 3 green balls in a bag. If one ball is drawn from the bag at random, what is the proba
Yuri [45]

Answer:

D.7/13

Step-by-step explanation:

Hope this helps :))

3 0
3 years ago
Could someone help me on question 1<br><br>thx
Ghella [55]
The answer is A!!! Hope that helped :)
4 0
2 years ago
Solve the equation using square roots.x2-14=-10
ElenaW [278]

Answer:

x=2

Step-by-step explanation:

x^{2} -14=-10\\

Add 14 to both sides

x^{2}=4

Square root it

x=2

8 0
3 years ago
Write the equation of a line that passes a given point and has the given slope. Answer in standard form. 1. Point (-3,5), m = -7
Likurg_2 [28]

Answer:

  1. y -5 = -7(x +3)
  2. y = 7

Step-by-step explanation:

The point-slope form of the equation can be used for this. It is generally written as ...

  y -k = m(x -h) . . . . . line with slope m through point (h, k)

__

1. For m=-7, (h, k) = (-3, 5), the equation is ...

  y -5 = -7(x +3)

__

2. For m=0, (h, k) = (4, 7), the equation is ...

  y -7 = 0(x -4)

  y = 7

_____

<em>Comment on the form of the answer</em>

Since a point and slope are given, "<em>the</em> equation" is appropriately written in point-slope form. For the second problem the simplified version would be ...

  y -7 = 0

Sometimes, "<em>the</em> equation" means the answer is expected in slope-intercept form. In that case, a little rearranging is necessary for the first answer. It becomes ...

  y = -7x -16

There are perhaps a dozen different forms that a linear equation can be written in. Considering those, "the equation" is somewhat ambiguous. Your curriculum materials may offer a clue as to the form intended.

5 0
3 years ago
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