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AleksandrR [38]
3 years ago
6

How many days in the month

Mathematics
1 answer:
iren2701 [21]3 years ago
7 0

January : 31 days.

February : February is the second and shortest month of the year in the Julian and Gregorian calendar with 28 days in common years and 29 days in leap years, with the quadrennial 29th day being called the leap day. It is the first of five months to have a length of less than 31 days, and the only month to have less than 30 days

March : 31 days.

April : 30 days.

May : 31 days.

June : 30 days.

July : 31 days.

August : 31 days.

Septembers : 30 days.

October : 31 days.

November : 30 days.

December : 31 days.



Hope this helps!

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xenn [34]

Answer:

y=0.5x+40

Step-by-step explanation:

Copy the  equation.

x-2y=8

Subtract x from both sides.

-2y=-x-8

Divide both sides by -2.

y=0.5x+4

Now we know the slope is 0.5.

Any line with a slope of 0.5 will be perpendiculr to the original line.

One that you can use is y=0.5x+40.

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Find the value of x and y​
Darina [25.2K]

\\ \rm\Rrightarrow \dfrac{x}{2}=3

\\ \rm\Rrightarrow x=2(3)

\\ \rm\Rrightarrow x=6

And

\\ \rm\Rrightarrow \dfrac{y}{2}+1=3

\\ \rm\Rrightarrow \dfrac{y}{2}=3-1=2

\\ \rm\Rrightarrow y=2(2)

\\ \rm\Rrightarrow y=4

5 0
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4 years ago
Find the value of k such that lim-->4 (x^2+x-k)/(x-4) exists
7nadin3 [17]

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Step-by-step explanation:

when x approaches 4, the denominator x-4 approaches 0

if the denominator is 0, it means that this is invalid

if the function is a number over 0 when x=4, it represents a vertical asymptote, which means no limit

so the only way possible to let there be a limit is to let the function be 0/0 when we plug in x=4

so x^2 + x - k = 0 when x = 4

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3 years ago
If f(x)= 5x, what is f^-1(x)?
Helen [10]

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8 0
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