Need help pleaseeeeeeeeee
1 answer:
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Answer:
or
Step-by-step explanation:
The given quadratic equation is
Group the constant terms on the right hand side.
Divide through by 5.
Add the square of half the coefficient of x., which is to both sides of the equation.
The left hand side is now a perfect square.
Take the square root of both sides;
or
or
or
The equation in slope-intercept form for the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5 is
<em><u>Solution:</u></em>
<em><u>The slope intercept form is given as:</u></em>
y = mx + c ----- eqn 1
Where "m" is the slope of line and "c" is the y - intercept
Given that the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5
Given line is perpendicular to − 4 x − 3 y = − 5
− 4 x − 3 y = − 5
-3y = 4x - 5
3y = -4x + 5
On comparing the above equation with eqn 1, we get,
We know that product of slope of a line and slope of line perpendicular to it is -1
Given point is (-1, -2)
Now we have to find the equation of line passing through (-1, -2) with slope
Substitute (x, y) = (-1, -2) and m = 3/4 in eqn 1
Thus the required equation of line is found
that's what I got, you can confirm if it's correct or not... I'm not sure
have a nice dayʘ‿ʘ
