Ask question

Ask question

All categories

3 years ago

12

I know this is akward and easy but my friend dosent believe me of this app just answer so she can believe me! Plssss number 11

2 answers:

Studentka2010 [4]3 years ago

7 0

Yes they represent the same number because the first one (a) goes by to each line and the bottom one (b) moves one over each line. (Idk if that made sense but yes lol I’m bad at explications)

Semmy [17]3 years ago

4 0

Both are the same because the first line is going by ×2 so the missing number would be 22. The second line is going by +1 so 21+1=22. (Hope this will prove your friend wrong :3)

You might be interested in

A company launches 4 new products. The market price, in dollars, of the 4 products after a different number of years, x, is show

marin [14]

The given functions appear to be ...

$f(x)=4x\\g(x)=2^x\\h(x)=x^2+12\\j(x)=x^3$

Of these, the exponential function g(x) will eventually exceed all others. That is the price of product 2, so ...

... The price of Product 2 will eventually exceed all others.

8 0

3 years ago

10%of what number is 14

Murrr4er [49]

I think 140 is the answer

3 0

4 years ago

Read 2 more answers

If x is the first of three consecutive even integers, write their sum as an algebraic expression in x.

zlopas [31]

(x) + (x + 2) + (x + 4)

8 0

3 years ago

Read 2 more answers

Which expression has a value of 24?

seraphim [82]

Answer:D

Step-by-step explanation: Use order of operations. Hope this helps!

8 0

3 years ago

Read 2 more answers

If √3 = 1.732, then √[(√3-1)/(√3+1)] is equal to

adelina 88 [10]

Step-by-step explanation:

<h3><u>Given Question :-</u></h3>

$\sf \: \sqrt{3} = 1.732, \: then \: \sqrt{\dfrac{ \sqrt{3} - 1}{ \sqrt{3} + 1} }$

$\red{\large\underline{\sf{Solution-}}}$

Given expression is

$\rm :\longmapsto\: \sqrt{\dfrac{ \sqrt{3} - 1}{ \sqrt{3} + 1} }$

<em>On rationalizing the denominator, we get </em>

$\rm \: = \: \sqrt{\dfrac{ \sqrt{3} - 1}{ \sqrt{3} + 1} \times \dfrac{ \sqrt{3} - 1}{ \sqrt{3} - 1} }$

$\rm \: = \: \sqrt{\dfrac{ {( \sqrt{3} - 1)}^{2} }{( \sqrt{3} + 1)( \sqrt{3} - 1)} }$

<em>We know, </em>

$\boxed{ \tt \: (x - y)(x + y) = {x}^{2} - {y}^{2} \: }$

<em>So, using this, we get </em>

$\rm \: = \: \dfrac{ \sqrt{3} - 1}{ \sqrt{ {( \sqrt{3})}^{2} - {(1)}^{2} } }$

$\rm \: = \: \dfrac{ \sqrt{3} - 1}{ \sqrt{ 3 - 1} }$

$\rm \: = \: \dfrac{ \sqrt{3} - 1}{ \sqrt{2} }$

$\rm \: = \: \dfrac{ \sqrt{3} - 1}{ \sqrt{2} } \times \dfrac{ \sqrt{2} }{ \sqrt{2} }$

$\rm \: = \: \dfrac{(1.732 - 1) \sqrt{2} }{2}$

$\rm \: = \: \dfrac{0.732 \times \sqrt{2} }{2}$

$\rm \: = \: 0.366 \sqrt{2}$

Hence,

$\rm :\longmapsto\: \boxed{ \rm{ \: \: \: \sqrt{\dfrac{ \sqrt{3} - 1}{ \sqrt{3} + 1} } = 0.366 \sqrt{2} \: \: \: }}$

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

<h2>More Identities to know :- </h2>

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)² = (a - b)² + 4ab

(a - b)² = (a + b)² - 4ab

(a + b)² + (a - b)² = 2(a² + b²)

(a + b)³ = a³ + b³ + 3ab(a + b)

(a - b)³ = a³ - b³ - 3ab(a - b)

3 0

3 years ago