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Anvisha [2.4K]
3 years ago
5

Find the side length, c.

Mathematics
1 answer:
Cloud [144]3 years ago
7 0

Answer:

C=14.9

Step-by-step explanation:

hope it´s right :)

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Find the interior angle of a regular polygon which has 6 sides​
AveGali [126]

Answer:

120°.

Step-by-step explanation:

The sum of all interior angles in a polygon with n sides (n\in \mathbb{Z}, n \ge 3) is equal to (n - 2) \cdot 180^{\circ}. (Credit: Mathsisfun.)

The polygon here has 6 sides. n = 6. Its interior angles shall add up to (6 - 2) \times 180^{\circ} = 720^{\circ}.

Consider the properties of a regular polygon. (Credit: Mathsisfun.)

  • All sides in a regular polygon are equal in length.
  • All angles in a regular polygon are also equal.

There are six interior angles in a polygon with 6 sides. All six of them are equal. Thus, each of the six interior angle will be

\displaystyle \frac{1}{6}\times 720^{\circ} = 120^{\circ}.

5 0
3 years ago
There are 3 3/4 cookies. if there is 1/4 of a cookie in each bag, how many bags are there?
Svetlanka [38]

Answer:

15 bags

Step-by-step explanation:

3 = 12/4

3 3/4 = 3+3/4 = 12/4 + 3/4 = (12+3)/4 = 15/4

(15/4) ÷ (1/4) = 15

5 0
2 years ago
Please help!!! thank you
fiasKO [112]

Answer:

28

Step-by-step explanation:

140 divided by 5 is 28

224 divided by 8 is 28

480 divided by 15 is 28

3 0
3 years ago
Read 2 more answers
Which statements accurately describe the function f(x) = 3(18)*? Select three options.
Yanka [14]

Answer:

Step-by-step explanation:

Without the variable x, your "f(x) = 3(18)*" is not a function.  If you meant

f(x) = 3(18)^x, then the domain is "the set of all real numbers," and the range is (0, infinity).

the initial value is 3:  f(0) = 3(18)^0 = 3(1) = 3

7 0
3 years ago
Suppose that g(x) = KX-6) - 3. Which statement best compares the graph
sukhopar [10]

Answer:

C

Step-by-step explanation:

Since g(x) =f(x-horizontal shift) - vertical shift.

So it will shift on the x-axis - 6 units so 6 units to the left and on the y-axis - 3 units so 3 units down.

4 0
3 years ago
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