Answer:
After 3 seconds while going up and 6 seconds while coming down
Step-by-step explanation:
Since projectile is launched from ground level with an initial velocity of v 0 feet per second, initial height =0
Height is given by
where v0 = initial velocity = 144
a) When h =288 ft.
At t= 3 or 6 seconds the projectile would be at height 288 ft.
So while going up after 3 seconds it wouldbe at a height of 288 ft and while coming after 6 seconds.
Answer:
59y+1
Step-by-step explanation:
25 + 8 (7y - 3) + 3y
Distribute
25+56y-24+3y
Combine like terms
59y+1
Answer: Planning because you need to start somewhere if you dont then you dont have any of the other steps
Good luck lovie :)
Hi there! The answer is A.
To get a proper idea of the type of function this formula represents we work out the parenthesis.
Working out the parenthesis can for instance be done using rainbow technique.
We can now see sinilarities between this function an the general function of a line in slope intercept form
The function t therefore describes a line with slope 2 and y-intercept 4. Therefore the answer is A.
2x^3 + 9x - 8 - (4x^2 - 15x + 7)....distribute thru the parenthesis
2x^3 + 9x - 8 - 4x^2 + 15x - 7....combine like terms
2x^3 - 4x^2 + 24x - 15 <==
