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katrin [286]
2 years ago
12

Sentence below is True or False.

Mathematics
1 answer:
Ket [755]2 years ago
5 0

Answer: False

Step-by-step explanation:

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13 is one third of a number<br> m
kicyunya [14]

Answer:39

Step-by-step explanation: 13 x 3= 39

3 0
3 years ago
Read 2 more answers
Choose the system of equations that matches the following graph: (5 points) picture of coordinate plane with line y equals negat
Grace [21]

Answer:

Option D

Step-by-step explanation:

To check whether (-2,2) is a solution to the system, let us substitute these values and check.

A. 3x − y = −4  

5x − y = −8

3(-2)-2=-8 is left side not equal to right side.

B. 3x − y = −4  

5x + y = −8

Since I equation is not satisfied not the matching system

C.3x + y = −4  

5x − y = −8  

I equation gives 3(-2)+2=-4

5(-2)-2 =-12

Since I equation is not satisfied not the matching system

Since II equation is not satisfied not the matching system

D. 3x + y = −4  

5x + y = −8

3(-2)+2=-4

5(-2)+2=-8

Thus D is the system which has solution (-2,2)

8 0
3 years ago
at a grocery store, salted peanuts in the shell cost .30 cents per ounce. Is $5.00 enough money to buy 1 pound of peanut? If it
love history [14]
Yeah 1 pound is $4.80 so you'll have $0.20 left
7 0
3 years ago
I just don't know how to do it
-BARSIC- [3]

Answer:

Do what exactly? Send a picture or an equation.

7 0
2 years ago
Convert the decimal number 183 into an equivalent 32 bit binary number. show all your work.
german
The bits are determined by repeated division by 2 to yield either 0 or 1.
 
183/2 = 91 rem 1  =>  1  (lowest bit)             2⁰
  91/2 = 45 rem 1  =>  1 (next higher bit)     2¹
  45/2 = 22 rem 1 => 1  (next higher bit)     2²
  22/2 = 11 rem 0  => 0 (next highrt bit)      2³
    11/2 = 5 rem 1    => 1 (next higher bit)     2⁴
     5/2 = 2 rem 1   => 1 (next higher bit)     2⁵
     2/2 = 1 rem 0   => 0 (next higher bit)    2⁶
     1/2 = 0 rem 1   => 1 (next higher bit)      2⁷
The next higher 24 bits have 0 in each bit.

For 32-bit system,
183 = 00000000 00000000 00000000 10110111 (with a space between bytes for readability)

Answer: 00000000000000000000000010110111

7 0
4 years ago
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