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Sauron [17]
3 years ago
10

Graph the linear equation using slope-intercept form. Y=-5/3x+4

Mathematics
1 answer:
Fiesta28 [93]3 years ago
7 0

Answer:

Graph is in the picture below

Step-by-step explanation:

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Which of the following is a linear equation<br>x+y-2<br>2x+5=11<br>15<br><br>​
skelet666 [1.2K]

Answer:

x + y = 2

y = 2 - x

so it is a linear equation.

2x + 5 = 11

2x = 11 - 5

2x = 6

x = 3

it is not a function because for just one <u>x</u> we have many <u>y</u>

5 0
3 years ago
One of your friends gives you $10 for a charity walkathon. Another friend gives you an amount per mile. After 5 miles, you have
irinina [24]
One of your friends gives you $10 for a charity walkathon -- this is your beginning amount.
Another friend gives you an amount per mile -- you will to calculate this value.
After 5 miles, you have raised $13.50 total --
-- Since one friend gave you $10.00, subtract this from the $13.50 to give you the amount by walking the 5 miles 
-- $10.00 - $13.50 = $3.50
-- Since you walked 5 miles, divide $3.50 by 5 to give you $0.70 per mile earned.

So, an equation that represents the amount of money earned is: y = $0.70x+$10.00.
This is in slope-intercept form; the slope is $0.70 and represents the amount of money earned per mile and the intercept is $10.00 and represents the initial amount of money that you were given.
7 0
4 years ago
If log 3 = x and log 5 = y, express log 45 in terms of x and y.
Marysya12 [62]

Answer:

I believe that the answer is A

5 0
2 years ago
34​% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a
finlep [7]

Answer:

a) There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

b) There is a 71.62% probability that more than two students use credit cards because of the rewards program.

c) There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

Step-by-step explanation:

There are only two possible outcomes. Either the student use credit cards because of the rewards program, or they use for other reason. So, we can solve this problem by the binomial distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem, we have that:

10 student are sampled, so n = 10

34% of college students say they use credit cards because of the rewards program, so \pi = 0.34

(a) exactly​ two

This is P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

(b) more than​ two

This is P(X > 2).

Either a value is larger than two, or it is smaller of equal. The sum of the decimal probabilities must be 1. So:

P(X \leq 2) + P(X > 2) = 1

P(X > 2) = 1 - P(X \leq 2)

In which

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{10,0}.(0.34)^{0}.(0.66)^{10} = 0.0157

P(X = 1) = C_{10,1}.(0.34)^{1}.(0.66)^{9} = 0.0808

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0157 + 0.0808 + 0.1873 = 0.2838

P(X > 2) = 1 - P(X \leq 2) = 1 - 0.2838 = 0.7162

There is a 71.62% probability that more than two students use credit cards because of the rewards program.

(c) between two and five inclusive

This is:

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

P(X = 3) = C_{10,3}.(0.34)^{3}.(0.66)^{7} = 0.2573

P(X = 4) = C_{10,4}.(0.34)^{4}.(0.66)^{6} = 0.2320

P(X = 5) = C_{10,5}.(0.34)^{5}.(0.66)^{5} = 0.1434

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1873 + 0.2573 + 0.2320 + 0.1434 = 0.82

There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

6 0
3 years ago
Example: y= -2x and y= x + 3<br> Does the point (0,4) make either equation true?
Alinara [238K]

Answer:

No it does not make either equation true

Step-by-step explanation:

If you substitute x, (0) and y (4) into the equation and solve, It doesn't end with a true statement.

8 0
3 years ago
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