Lang atino<br> Determine whether a triangle can be formed with the<br> 5. 10 ft, 3 ft, 15 ft

If 35 J of work was performed in 70 seconds, how much power was used to do this task

tiny-mole [99]

Answer:

I believe the answer is 0.5 !

Step-by-step explanation:

The formula for power is:

P = work / time

P = 35J / 70s

P = 0.5

5 0

4 years ago

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40 points!!!!!PLEASE HELP!!!!

Alex17521 [72]

Answer: $\frac{\sqrt{26}}{26}$

This is the square root of 26 over 26. The second 26 is not inside the square root. You can type it in as sqrt(26)/26.

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$\theta$ is in Q1 so $\sin(\theta) > 0$

Use the trig identity below and plug in the given value to get...

$\sin\left(\frac{x}{2}\right) = \pm \sqrt{\frac{1-\cos(x)}{2}}\\\\\sin\left(\frac{2\theta}{2}\right) = \pm \sqrt{\frac{1-\cos(2\theta)}{2}}\\\\\sin(\theta) = \sqrt{\frac{1-\cos(2\theta)}{2}} \ \ \text{since } \ \sin(\theta) > 0\\\\\sin(\theta) = \sqrt{\frac{1-\frac{12}{13}}{2}}\\\\$

$\sin(\theta) = \sqrt{\frac{1}{26}}\\\\\sin(\theta) = \frac{\sqrt{1}}{\sqrt{26}}\\\\\sin(\theta) = \frac{1}{\sqrt{26}}\\\\\sin(\theta) = \frac{1*\sqrt{26}}{\sqrt{26}*\sqrt{26}} \ \ \text{ rationalizing denominator}\\\\\sin(\theta) = \frac{\sqrt{26}}{26}\\\\$

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Edit:

To find cos(theta), we use the pythagorean identity below

$\sin^2(\theta) + \cos^2(\theta) = 1\\\\\cos^2(\theta) = 1-\sin^2(\theta)\\\\\cos(\theta) = \sqrt{1-\sin^2(\theta)}\ \ \text{cosine is positive in Q1}\\\\\cos(\theta) = \sqrt{1-\left(\frac{1}{\sqrt{26}}\right)^2}\\\\\cos(\theta) = \sqrt{1-\frac{1}{26}}\\\\\cos(\theta) = \sqrt{\frac{25}{26}}\\\\\cos(\theta) = \frac{\sqrt{25}}{\sqrt{26}}\\\\\cos(\theta) = \frac{5}{\sqrt{26}}\\\\\cos(\theta) = \frac{5\sqrt{26}}{\sqrt{26}*\sqrt{26}}\\\\\cos(\theta) = \frac{5\sqrt{26}}{26}\\\\$

6 0

3 years ago

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BRAINLIEST ....................................

qaws [65]

9514 1404 393

Answer:

(b) 7720 mm² of paper

Step-by-step explanation:

The central horizontal rectangle of the net is 80 mm high and ...

40 + 5.5 + 40 + 5.5 = 91

mm long. Its area 9 is ...

(80 mm)(91 mm) = 7280 mm²

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The two pieces of the net not accounted for above are the "flaps" above and below the central rectangle. Each of those two has an area of 40 mm by 5.5 mm, so their total area is ...

2(40 mm)(5.5 mm) = 440 mm²

Then the area of paper needed for the wrapper is ...

total area = 7280 mm² + 440 mm²

total area = 7720 mm²

8 0

3 years ago

PLZ HELP WITH THESE 2 QUESTIONS!

LUCKY_DIMON [66]

1) answer is D
pentagon with each side 5 inches
5x5=25

2)A perimeter is 27 and B perimeter is 24 so perimeter A is greater than B

5 0

4 years ago

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Rahul solved the equation 2(x – 1/8 ) – 3/5x = 55/4. In which step did he use the addition property of equality? A. Step 1 B. St

Taya2010 [7]

Answer:

x=10 is answer.

Step-by-step explanation:

2 (x-1/8)-3/5x=55/4

2x/1-1/4-3/5=55/4

40x/20-5/20-12x/20=55/4

28x-5/20=55/4

112x-20=1100

112x=1120

x=1120/112

x=10

7 0

3 years ago

Lang atino Determine whether a triangle can be formed with the 5. 10 ft, 3 ft, 15 ft