Answer:m=250
Step-by-step explanation:
0.1m+8-3=30
0.1m+5=30
0.1m=25
0.1 times 250=25
m=250
Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5
Just turn the percentage to a decimal. 145% becomes 1.45. Then add 1.00 to 1.45. 1 + 1.45 = 2.45
Then multiply. 2.45 * 340 = 833
Px = missing length
xy = 3
Py = 6
these are the 3 sides of a right triangle; let's use the Pythagorean theorem to find Px
(Px)² + 3² = 6² subtract 3² from both sides
(Px)² = 36 - 9 simplify the right
(Px)² = 27 take the square root of both sides
Px =
Px =
Final Result :
79 - 216x
Processing ends successfully
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