What is the potential energy of a 500-N pole-vaulter when she is 4 m above the ground?
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Answer
A. Many solution
Step by step explanation
Points on line 1 : (-3, 6) and (3, 4)
Points on line 2: (-6, 7) and (9, 2)
Now let's find the slope of the line 1
Slope formula =
Slope of line 1 = (4 - 6) / (3 - (-3)
= -2/(3 + 3)
= -2/6
Slope of line 1 = -1/3
The equation of the line y - y 1 = m(x - x1)
y - 6 = -1/3 (x - (-3))
y -6 = -1/3 (x + 3)
y -6 = -1/3x - 1
y = -1/3x + 5
Slope of line 2 = (2 - 7) / (9 -(-6))
= -5/(9 + 6)
= -5/15
Slope of line 2 = -1/3
The equation of line
y - y1 = m(x - x1)
y - 7 = -1/3(x - (-6))
y - 7 = -1/3(x + 6)
y -7 = -1/3 x - 2
y = -1/3 x + 5
The line 1 and line 2 have the same slopes and the same y-intercept. Both are the same equation. Therefore, there will be many solution.
Answer : A. 0 Solution
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