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3 years ago

Help me with this!!! Will mark Brainliest!! ❤️

Mathematics

2 answers:

valina [46]3 years ago

8 0

Answer:

Step-by-step explanation:

EF=1

FG=2

1 is not equal to 2

Hope this helps :D

Tatiana [17]3 years ago

3 0

Answer:

Step-by-step explanation:

to be congruent means to be identical fg is longer than ef so they are not congruent

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Write 3 numbers that make this inequality true: x>4

Trava [24]

Answer:

8, 10, 24

(Basically every number above 4)

5 0

3 years ago

Read 2 more answers

PLS HELP!!! FIRST ANSWER GETS BRAINLIEST!!!

olga55 [171]

Answer:C

Step-by-step explanation:11m is the radius and to find the diameter u multiply 11 x 2 which is radius x 2 which = 22

5 0

3 years ago

Emily took 300 US dollars to the bank to exchange it for Canadian dollars. The exchange rate on that day was 1.25 Canadian dolla

Paha777 [63]

Emily wanted to exchange her 300 US Dollars for Canadian Dollars.

The exchange rate for it was 1.25 Canadian Dollars for 1 US Dollar.

This means that 1 US Dollar = 1.25 Canadian Dollars.

So if we were to follow this pattern,

2 US Dollars = 2 × 1.25 = 2.5 Canadian Dollars

3 US Dollars = 3 × 1.25 = 3.75 Canadian Dollars

4 US Dollars = 4 × 1.25 = 5 Canadian Dollars

So for 300 US Dollars, we'll need to multiply 300 by 1.25.

300 US Dollars = 300 × 1.25 = 375 Canadian Dollars.

Hope it helps. :)

4 0

3 years ago

30 years ago zoe was 2/3 as old as luke, 18 years ago zoe was 5/6 as old as luke how old are they now

barxatty [35]

Based on the mathematical statements, Zoe is 56 years old and Luke is 66 years old, now

<h3>How to determine how old they are now?</h3>

From the question, we have the following statements that can be used in our computation:

30 years ago

Zoe was 2/3 as old as Luke

18 years ago

Zoe was 5/6 as old as Luke

Let their present ages be represented as

Zoe = x

Luke = y

So, we have the following representations

30 years ago

Zoe was 2/3 as old as Luke

x - 36 = 2/3(y - 36)

18 years ago

Zoe was 5/6 as old as Luke

x - 18 = 5/6(y - 18)

So, we have the following system of equations

x - 36 = 2/3(y - 36)

x - 18 = 5/6(y - 18)

Make x the subject in x - 18 = 5/6(y - 18)

x = 5/6(y - 18) + 16

Substitute x = 5/6(y - 18) + 16 in x - 36 = 2/3(y - 36)

5/6(y - 18) + 16 - 36 = 2/3(y - 36)

Open the brackets

5/6y - 15 + 16 - 36 = 2/3y - 24

Evaluate the like terms

5/6y - 35 = 2/3y - 24

Multiply through by 6

5y - 210 = 4y - 144

Evaluate the like terms

y = 66

Substitute y = 66 in x = 5/6(y - 18) + 16

x = 5/6(66 - 18) + 16

Evaluate

x = 56

Recall that

Zoe = x

Luke = y

So, we have

Zoe = x = 56

Luke = y = 66

Hence, they are 56 and 66 years, now

Read more about equations at

brainly.com/question/2476251

#SPJ1

5 0

11 months ago

Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]

alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

$\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]$

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)² = 3√6

Therefore, the unit vector is

$\frac{[7,2,-1]}{3\sqrt{6} }$

[ $\frac{7}{3\sqrt{6} }$ , $\frac{2}{3\sqrt{6} }$ , $\frac{-1}{3\sqrt{6} }$ ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ $\frac{-7}{3\sqrt{6} }$ , $\frac{-2}{3\sqrt{6} }$ , $\frac{1}{3\sqrt{6} }$ ]

In conclusion, the two unit vectors are;

[ $\frac{7}{3\sqrt{6} }$ , $\frac{2}{3\sqrt{6} }$ , $\frac{-1}{3\sqrt{6} }$ ]

and

[ $\frac{-7}{3\sqrt{6} }$ , $\frac{-2}{3\sqrt{6} }$ , $\frac{1}{3\sqrt{6} }$ ]

Hope this helps!

7 0

2 years ago