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tigry1 [53]
3 years ago
13

Can answer this question ASAP

Mathematics
1 answer:
iogann1982 [59]3 years ago
8 0

Answer:

The answer is 108ft^2

Please mark me brainliest

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What is the digit in 913 and where's the digit in the tens place and the value of the digit tens someone answer for my homework
lorasvet [3.4K]
4. Period with the digits 913 is called thousands period.
5. The digit in the ten thousand place is 1.
6. The value of 9 is hundred thousands.

Hope it will help you :)
3 0
3 years ago
Read 2 more answers
Please help! acellus
ch4aika [34]

Answer:

The number that belongs <em>in</em> the green box is equal to 909.

General Formulas and Concepts:
<u>Algebra I</u>

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Trigonometry</u>

[<em>Right Triangles Only</em>] Pythagorean Theorem:
\displaystyle a^2 + b^2 = c^2

  • a is a leg
  • b is another leg
  • c is the hypotenuse

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given variables</em>.

<em>a</em> = 30

<em>b</em> = 3

<em>c</em> = <em>x</em>

<em />

<u>Step 2: Find </u><u><em>x</em></u>

Let's solve for the <em>general</em> equation that allows us to find the hypotenuse:

  1. [Pythagorean Theorem] Square root both sides [Equality Property]:
    \displaystyle \begin{aligned}a^2 + b^2 = c^2 \rightarrow c = \sqrt{a^2 + b^2}\end{aligned}

Now that we have the <em>formula</em> to solve for the hypotenuse, let's figure out what <em>x</em> is equal to:

  1. [Equation] <em>Substitute</em> in variables:
    \displaystyle \begin{aligned}c & = \sqrt{a^2 + b^2} \\x & = \sqrt{30^2 + 3^2}\end{aligned}
  2. <em>Evaluate</em>:
    \displaystyle \begin{aligned}c & = \sqrt{a^2 + b^2} \\x & = \sqrt{30^2 + 3^2} \\& = \boxed{ \sqrt{909} } \\\end{aligned}

∴ the hypotenuse length <em>x</em> is equal to √909 and the number <em>under</em> the square root, our answer, is equal to 909.

___

Learn more about Trigonometry: brainly.com/question/27707750

___

Topic: Trigonometry

3 0
2 years ago
Please work out the shapes question pls!!!
Contact [7]
Here's what I got for the first question.

Did you want answers for the second one? I couldn't read that part of the image very well, if you did.

7 0
3 years ago
Fill in the other coordinate for the line 7x - 5y = 21: (4, )
garri49 [273]
7x - 5y = 21....(4,?)...so sub in 4 for x and solve for y
7(4) - 5y = 21
28 - 5y = 21
-5y = 21 - 28
-5y = - 7
y = 7/5

check..
7(4) - 5(7/5) = 21
28 - 35/5 = 21
28 - 7 = 21
21 = 21 (correct)

the other coordinate is 7/5......(4,7/5)
8 0
3 years ago
Here is an equilateral triangle. The length of each side is units. A height is drawn. In an equilateral triangle, a line drawn f
Temka [501]

1. Height of the equilateral triangle is: √3 units

2. Area of the equilateral triangle = √3 units²

3. Area = √3/4 x², when each side is x.

<h3>What is an Equilateral Triangle?</h3>

A triangle that has all its three sides equal in length, is referred to as an equilateral triangle.

1. Given the each side measures 2 units, and h is the height, applying the Pythagorean theorem, we would have:

h = √(2² - 1²)

h = √(4 - 1)

h = √3

2. Area of the equilateral triangle = 1/2bh = 1/2(2)(√3)

Area of the equilateral triangle = √3 units²

3. If x is the side length of the equilateral triangle, we would have:

height (h) = √[x² - (x/2)²] = √[x² - x²/4] = √(3x²/4) = √3/2x

Area = 1/2bh = 1/2(x)(√3/2x) = √3/4 x²

Learn more about equilateral triangle on:

brainly.com/question/15294703

#SPJ1

3 0
2 years ago
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