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3 years ago

The surface area of a cylinder is 602.88. If the dimensions of the cylinder are

Mathematics

1 answer:

lana66690 [7]3 years ago

3 0

Answer:

you all have to divide by 2

Step-by-step explanation:

602.88÷2= 301.44

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How to find displacement from velocity.

Ipatiy [6.2K]

Answer:

The average velocity of the object is multiplied by the time traveled to find the displacement. The equation x = ½( v + u)t can be manipulated, as shown below, to find any one of the four values if the other three are known.

5 0

3 years ago

What is the product of 14560 times 10

Andrews [41]

The product of 14560 and 10 is 145600

3 0

3 years ago

Find the GCF <img src="https://tex.z-dn.net/?f=32xy-18%20x%5E%7B2%7D%20" id="TexFormula1" title="32xy-18 x^{2} " alt="3

eduard

The GCF is the largest number that can go into both the terms. Since "y" isn't in both terms, it can't include y. x, however, is, so we know our GCF has x in it. What's the largest whole number that can go into 32 and 18? 2. Your GCF is 2x.

Don't forget to rate this answer the Brainliest!

4 0

3 years ago

Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ

atroni [7]

Answer: $y=Ce^(^3^t^{^9}^)$

Step-by-step explanation:

Beginning with the first differential equation:

$\frac{dy}{dt} =27t^8y$

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

$\frac{1}{y} \frac{dy}{dt} =27t^8$

Multiply both sides by 'dt' to get:

$\frac{1}{y}dy =27t^8dt$

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

$\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt$

$ln(y)=27(\frac{1}{9} t^9)+C$

$ln(y)=3t^9+C$

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

$e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)$

$y=e^(^3^t^{^9} ^+^C^)$

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

$y=e^(^3^t^{^9}^)e^C$

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

$y=Ce^(^3^t^{^9}^)$

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

$\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8$

Now check if the derivative equals the right side of the original differential equation:

$(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)$

$Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)$

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0

2 years ago

The elevation is 12,000 feet. the altimeter reading in an airplane is 17.00 in hg. this pressure is equal to

In-s [12.5K]

The elevation is 12,000 feet. the altimeter reading in an airplane is 17.00 in hg. this pressure is equal to:
There are 29.92inHg in 1 atm
thus
17 inHg×(1 atm/29.92inHg)
=17/29.92
=0.5682 atm

Answer: 0.5682 atm

7 0

3 years ago