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AveGali [126]
2 years ago
10

What are my zeros (x^2 - 8x + 1)?

Mathematics
1 answer:
Pavel [41]2 years ago
7 0

Answer:

x= 7.87298334621                          x=.12701665379

Step-by-step explanation:

This is in standard form so we have to factor this into

x^2-8x + 16 + 1 = 16

(x-4)^2 = 15

(x-4) = \sqrt{15\\}

x-4= ± 3.87298334621

x-4 = 3.87298334621                      x-4= -3.87298334621

x= 7.87298334621                          x=.12701665379

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