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kykrilka [37]
3 years ago
5

. A soccer ball manufacturer claims the diameters of their ball have a standard deviation of 2 mm when properly inflated. Based

on a random sample of 10 balls you find a standard deviation of 3.2 mm. Does the sample suggest the standard deviation is higher than that claimed by the manufacturer?
Mathematics
1 answer:
levacccp [35]3 years ago
4 0

Answer:

Yes, there is significant evidence to support the claim that sample standard deviation is higher than that claimed by the manufacturer

Step-by-step explanation:

Sample standard deviation, s = 3.2

Population standard deviation, σ = 2

Defining the Null and alternative hypothesis :

H0 : σ = 2

H1 : σ > 2

The test statistic :

Use the Relation :.

[(n - 1)*s²] ÷ σ²

[(10 - 1) * 3.2²] ÷ 2²

(9 * 10.24) ÷ 4

92.16 ÷ 4

= 23.04

We obtain the Pvalue for the distribution :

Using the Pvalue from Chisquare distribution calculator :

Pvalue(Chisquare score, df)

df = n - 1 = 10 - 1 = 9

Pvalue(23.04, 9) = 0.006107

Decision :

If Pvalue is < α ; Reject H0 ; α = 0.05

0.006107 < 0.05 ; We reject H0

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-2/3x+7(3/7-3/7x) -12 divided by 6*3
Anna71 [15]

Answer:

x = (-27)/11

Step-by-step explanation:

Solve for x:

(-11 x)/54 - 1/2 = 0

Put each term in (-11 x)/54 - 1/2 over the common denominator 54: (-11 x)/54 - 1/2 = (-27)/54 - (11 x)/54:

(-27)/54 - (11 x)/54 = 0

(-27)/54 - (11 x)/54 = (-11 x - 27)/54:

(-11 x - 27)/54 = 0

Multiply both sides of (-11 x - 27)/54 = 0 by 54:

(54 (-11 x - 27))/54 = 54×0

(54 (-11 x - 27))/54 = 54/54×(-11 x - 27) = -11 x - 27:

-11 x - 27 = 54×0

0×54 = 0:

-11 x - 27 = 0

Add 27 to both sides:

(27 - 27) - 11 x = 27

27 - 27 = 0:

-11 x = 27

Divide both sides of -11 x = 27 by -11:

(-11 x)/(-11) = 27/(-11)

(-11)/(-11) = 1:

x = 27/(-11)

Multiply numerator and denominator of 27/(-11) by -1:

Answer:x = (-27)/11

5 0
3 years ago
The stemplot displays the selling prices of homes for ABC Realty in April.
Alexxandr [17]

The stemplot displays the entire values for the selling prices of homes for ABC Reality in April.

The correct set of data for the stemplot is the option;

  • <u>$459,000, $227,000, $67,000, $123,000, $213,000, $482,000, $85,000, $181,000, $225,000, $92,000, $181,000, $287,000, $196,000, $276,000</u>

<h3>Method by which the above option is selected</h3>

The data in the stemplot are;

459,000, 482,000, 213,000, 225,000, 276,000, 277,000, 287,000, 123,000, 181,000, 181,000, 196,000, 67,000, 85,000, 92,000

Given that there are no values in the 300,000s, and that 181,000 appear twice, the option that corresponds to the above data is therefore;

  • $459,000, $277,000, $67,000, $123,000, $213,000, $482,000, $85,000, $181,000, $225,000, $92,000, $181,000, $287,000, $196,000, $276,000

Learn more about stemplot here:

brainly.com/question/10572086

6 0
2 years ago
#1). Yasmine plans to attend a four-year public university. She expects she will need to contribute $9,000 annually to her educa
Nina [5.8K]
The answer to #1 is D.

The answers to #2 is B,C,D,F.. I'm not sure what the remainder of G says..
3 0
3 years ago
Read 2 more answers
When Joseph finished packing his backpack, it had a mass of 5 kilograms. What was the mass of the backpack in grams
worty [1.4K]
There is 1000 grams in a kilogram so he had a mass of 5,000 grames in his bag
7 0
4 years ago
SOMEONE HELP ME PLEASE WITH THESE PROBLEMS AND PLEASE SHOW YOUR WORK FOR 50 points and BRAINLIEST THANK YOU
ELEN [110]

<u>Answer</u>:

13. 6x^7 y^7   ||     14. \frac{25x^4}{y^6}

<u>explanation</u>:

13.

\frac{12x^9 y^5}{2x^2 y^-2}

6x^{9-2} y^{5--2}

6x^7 y^7

14.

(\frac{5y^{-3} }{x^{-2} } )^{2}

(\frac{5y^{-3} }{x^{-2} } )(\frac{5y^{-3} }{x^{-2} } )

\frac{\frac{25}{y^6}}{\left(x^{-2}\right)^2}

\frac{\frac{25}{y^{-6} }}{\left(x^{-4}\right)}

\frac{25x^4}{y^6}

4 0
2 years ago
Read 2 more answers
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