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3 years ago

Andtonnes3/4314tonnes

Mathematics

1 answer:

solniwko [45]3 years ago

8 0

What do you mean? Pls state the question correctly

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Solve the inequality for y. y + 4x < -3

Olin [163]

Answer:

$\huge \boxed{y$

Step-by-step explanation:

$y + 4x < -3$

Subtracting 4x from both sides of the inequality.

$y + 4x -4x< -3-4x$

Simplifying the inequality.

$y$

4 0

3 years ago

justin wants to buy shorts that cost $35 and some shirts that are on sale for $22 each. He has $95 to spend. Write an inequality

Ostrovityanka [42]

35 plus 22 -95 equal left seat on the right pole then pause

4 0

3 years ago

The product of five rational numbers is positive. At most, of these rational numbers can be negative

Ivanshal [37]

Answer: A. 1

Step-by-step explanation:

sorry if im wrong

5 0

3 years ago

En un grupo de 100 personas 2/5 prefieren sopa de pollo, 4/10 prefieren comer hornado, y el resto prefiere fritada. A) ¿Qué part

castortr0y [4]

In a group of 100 people, 2/5 prefer chicken soup, 4/10 prefer to eat hornado, and the rest prefer frying. What part of the group prefers frying ? How many people prefer each type of food ? (thank u google translate)...I guess

2/5 of 100 prefer chicken soup.....so thats 2/5 * 100 = 200/5 = 40 prefer chicken soup.

4/10 out of 100 prefer hornado (I dont even know what that is)...
4/10 * 100 = 400/10 = 40 prefer hornado.

and the rest prefer frying....100 - (40 + 40) = 100 - 80 = 20 (or 1/5) prefer frying

3 0

3 years ago

EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att

aliina [53]

$y=x(x-2)^2$
$\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0$
$\implies x=\dfrac23,x=2$

are the critical points, and judging by the picture alone, you must have $b=\dfrac23$ and $a=2$ . (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

$\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43$

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of $\dfrac{\mathrm dy}{\mathrm dx}=y'$ , which entails first finding the second derivative:

$y'=3x^2-8x+4$
$\implies y''=6x-8$

setting equal to 0 and finding the critical point:

$6x-8=0\implies x=\dfrac86=\dfrac43$

This is to say the minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ *occurs when $x=\dfrac43$ *, but this is not necessarily the same as saying that $\dfrac43$ is the actual minimum value.

The minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ is obtained by evaluating the derivative at this critical point:

$m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43$

4 0

4 years ago

Andtonnes3/4314tonnes​

Andtonnes3/4314tonnes