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The ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1
<h3>Ratio of the areas of similar figures </h3>From the question, we are to determine the ratio of the area of the<u> first figure</u> to the area of the <u>second figure</u>
<u />
The two figures are similar
From one of the theorems for similar polygons, we have that
If the scale factor of the sides of <u>two similar polygons</u> is m/n then the ratio of the areas is (m/n)²
Let the base length of the first figure be ,m = 14 mm
and the base length of the second figure be, n = 7 mm
∴ The ratio of their areas will be
= 4:1
Hence, the ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1
Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446
Step-by-step explanation:
Nicole starts with the budget:
$395
Now, she only expects to pay half the deposit;
$72 ÷ 2 = $36
Subtract this from the budget:
$395 - $36 = $359
Divide by cost per hour:
$359 ÷ $60 = 5.983333... (3 repeating)
This means, Nicole can rent a <em>maximum</em><em> </em>of 5 hours with her budget. The inequality would be