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lesantik [10]
3 years ago
5

A club collected $3,472 to buy computers. If each computer cost $680, estimate the number of computers that the club can buy.exp

lain
Mathematics
1 answer:
almond37 [142]3 years ago
8 0

The club can buy 5 computers with $3472

Step-by-step explanation:

The number of computers which can be bought from the given amount will be calculated by dividing the amount by price of one computer.

Given

Total amount = $3472

Price of one computer =$680

The number of computers will be:

=\frac{Total\ amount}{Price\ per\ computer}\\=\frac{3472}{680}\\=5.1\\

As the number of an item cannot be in decimal it will be rounded off to 5.

The club can buy 5 computers with $3472

Keywords: Price per unit, pricing

Learn more about pricing at:

  • brainly.com/question/7287774
  • brainly.com/question/726990

#LearnwithBrainly

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One person gets 3 10ths of it and the other gets 7 10ths

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The question is below​
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Answer:

See below.

Step-by-step explanation:

a.

The first figure has 1 square. The second figure has a column of 2 squares added to the left. The third figure has a column of 3 squares added to the left. Each new figure has a column of squares added to the left containing the same number of squares as the number of the figure.

b.

Figure 10 has 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55 squares.

c.

The formula for adding n positive integers starting at 1 is:

1 + 2 + 3 + ... + n = n(n + 1)/2

For figure 55, n = 55.

n(n + 1)/2 = 55(56)/2 = 1540

d.

Let's use the formula set equal to 190 and solve for n. If n is an integer, then we can.

n(n + 1)/2 = 190

n(n + 1) = 380

We know that 380 = 19 * 20, so n = 19.

Answer: yes

e.

Use the formula above,

S = n(n + 1)/2, where S is the sum.

f.

n(n + 1) = 1478

38 * 39 = 1482

37 * 38 = 1406

3 0
3 years ago
A factory used 7/10 of a barrel of almonds to make 7 batches of granola bars. How many barrels of almonds did the factory put in
zlopas [31]

Answer:

4 9/10

Step-by-step explanation:

7/10×7=49/10= 4 9/10

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Please help! For the function f(x) = 2x^6 + 3x^4 - 4x^3 + (1/x) - sin(2x) find the first four derivatives.
klasskru [66]

Answer:

See the explanation

Step-by-step explanation:

We know that

f(x) = 2x⁶ + 3x⁴ - 4x³ + (1/x) - sin2x

Lets calculate the derivatives:

f'(x) = 6(2x⁵) + 4(3x³) - 3(4x²) -( 1/x²) - 2(cos2x)

f'(x) = 12x⁵ + 12x³ - 12x² - (1/x²) - 2cos2x

Similarly:

f''(x) = 60x⁴ + 36x² - 24x + (2/x³) + 4sin2x

f'''(x) = 240x³ + 72x - 24 - (6/x⁴) + 8cos2x

Rearrange:

f'''(x) - 240x³ +72x - (6/x⁴) + 8cos2x - 24

f''''(x) = 720x² + 72 + (24/x⁵) - 16sin2x

Rearrange:

f''''(x) = 720x² + (24/x⁵) - 16sin2x +72

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