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Valentin [98]
2 years ago
8

I need help pls :) <3

Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
5 0

Answer:

x-3y ≥ -4

Step-by-step explanation:

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If B = {−13, −9, −7, −3}, choose the set A that will make the following statement false.
Svetach [21]

Answer: c.A is the set of rational numbers

Step-by-step explanation:

B ⊆ A means that every element of B is an element of A

B = { -13 , -9 , -7 , - 3 }

The element of B are negative integers , this mean that the element of A must also be integers therefore :

Option a is correct.

Option b is also correct

Rational numbers are numbers that can be express in the form a/b , examples are : 1/2 , 3/ 4 , 5/6 ...

clearly , this does not necessarily define A , so option c is the odd one out

5 0
3 years ago
Please help!... its due tonight and i need help
myrzilka [38]
It’s the last one (10,800)
3 0
3 years ago
Read 2 more answers
PLEASE HELP ITS DUE TODAY!!!Answer the following questions that a sales associate is asking you. Write 2 sentences in Spanish fo
kirza4 [7]

Answer:

1) ¿Puedes ayudarme a encontrar ropa?

2) Estoy buscando una camisa y un par de zapatos.

3)  Sí. Veo una camisa azul y un par de zapatos blancos.

4) Llevo 3 camisas y 2 pares de zapatos.

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8 0
2 years ago
√48a^4 b^5 c^3 d simplify and keep it in radical form
Morgarella [4.7K]
I will assume the square root extends all the way across.

\sqrt{48a^4b^5c^3}

\sqrt{2^4\cdot3\cdot a^4b^5c^3}

\sqrt{(2^2)^2\cdot3\cdot(a^2)^2\cdot(b^2)^2\cdot b\cdot c^2\cdot c}

\sqrt{(4)^2\cdot3\cdot(a^2)^2\cdot(b^2)^2\cdot b\cdot c^2\cdot c}

\sqrt{(4\cdot a^2 \cdot b^2 \cdot c)^2\cdot3\cdot b\cdot c}

4\cdot a^2\cdot b^2\cdot c\sqrt{3\cdot b\cdot c}

\boxed{4a^2b^2c\sqrt{3bc}}






3 0
3 years ago
|6t−7|−8 ≥ 3 Please help me quick
Phantasy [73]
Hope the answer helps you!!!
:)

5 0
2 years ago
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