X - 3/8 = 13/2
Add 3/8 to both sides:
X = 13/2 + 3/8
Rewrite 13/2 to have 8 as the denominator:
13/2 x 4 = 52/8
X = 52/8 + 3/8
X = 55/8
The question is incomplete, the complete question is;
A factory produces 1,250,000 toys each year. The number of toys is expected to increase by about 150% per year. Which model can be used to find the number of toys being produced, n (in millions), in t years?
A. n= 2.5(1.5)/t, t cannot = 0
B. n= 1.5t^2 + 1.25
C. n= 1.5t + 1.25
D. n= 1.25(2.5^t)
Answer:
D. n= 1.25(2.5^t)
Step-by-step explanation:
This is an exponential growth problem. In mathematics, for an exponential growth problem;
P = Po(1 + r)^t
Where;
P= amount at time t
Po =initial amount
r= rate
t= time
In the context of the question we have;
n= 1.25(1 + 150/100)^t
n= 1.25(2.5)^t
$78.90 cents
Hope this helps
Answer:
Amplitude 3; midline y=2
Step-by-step explanation:
The midline is the mean of both ends of the function in the graph.
The amplitude is the vertical distance between the midline and one of the end points.
(sorry for the basic math, i just want to make sure you know where im getting the values from)
Answer:
Step-by-step explanation:0.828282 = 0.828282/1 = 8.28282/10 = 82.8282/100 = 828.282/1000 = 8282.82/10000 = 82828.2/100000 = 828282/1000000
And finally we have:
0.828282 as a fraction equals 828282/1000000
