3 years ago

Can someone help me plz

Mathematics

1 answer:

kolezko [41]3 years ago

8 0

Answer: 7.21

Step-by-step explanation: Plug points into $\sqrt{(x^2-x^1)^2+(y^2-y^1)^2}$

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One number exceeds another by 2 the sum of the number is 48 what are the numbers

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$x-\ first\ number\\y-\ second\ number\\\\
 \left \{ {{x-y=2} \atop {x+y=48}} \right. \\\\ \left \{ {{x=2+y} \atop {x+y=48}} \right. \\\\Substution\ method\\\\
2+y+y=48\\\\
2+2y=48\\\\
2y=46\ \ \ |:2\\\\
\boxed{y=23}$

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4 years ago

Mademuasel [1]

I hope this helps you

take both of sides paranthesis square

(2a+7b)^2=(11)^2

4a^2+2.4a.7b+49b^2=121

4a^2+49b^2+56.2=121

4a^2+49b^2=9

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2 years ago

Can someone help me plz​

Can someone help me plz