Answer:
the probability that a code word contains exactly one zero is 0.0064 (0.64%)
Step-by-step explanation:
Since each bit is independent from the others , then the random variable X= number of 0 s in the code word follows a binomial distribution, where
p(X)= n!/((n-x)!*x!*p^x*(1-p)^(n-x)
where
n= number of independent bits=5
x= number of 0 s
p= probability that a bit is 0 = 0.8
then for x=1
p(1) = n*p*(1-p)^(n-1) = 5*0.8*0.2^4 = 0.0064 (0.64%)
therefore the probability that a code word contains exactly one zero is 0.0064 (0.64%)
1) side BD is common
2) angle ABD is equal to angle BDC (alternate angles)
3) angle CBD is equal to angle ADB (alternate angles)
Y=-1/2x + 2
I’m pretty sure that this is the answer :))
Answer is 6/4 your welcome bro
Answer:
No
Explanation:
The distance between the two points on the ground = 43km

First, we calculate the distance between the two points in meters.
• 43km = 43,000 m.
Next, determine the distance it will take using the scale.

The distance between the points using the scale is 1.72m.
Next, we see that the dimensions (1.32 m by 0.85 m) are smaller than the length.
As a final check, calculate the length of the diagonal of the map. The diagonal is usually the longest part.
![\text{Diagonal}=\sqrt[]{1.32^2+0.85^2}=1.57m](https://tex.z-dn.net/?f=%5Ctext%7BDiagonal%7D%3D%5Csqrt%5B%5D%7B1.32%5E2%2B0.85%5E2%7D%3D1.57m)
Since 1.57m is still less than 1.72m, the two points cannot be placed on the map.