To find the area of the shaded region you need find the area
of the shaded region and subtract the area of the unshaded region.
Area of a rectangle = width x length
A = (x + 10) x (2x + 5)
Next apply FOIL or
First Outer Inner Last
A = (x * 2x) (x * 5) (10 * 2x) (10 * 5)
A= 2x2 + 5x + 20x + 50
A= 2x2 +25x +50
Area of a square= sides2
A= (x + 1)2
A= (x+1) (x+1)
Next apply FOIL or
First Outer Inner Last
A = (x *x) (1*x) (1*x) (1*1)
A = x2 + 1x + 1x +1
A= x2 + 2x +1
A= 2x2 +25x +50 - 2x2 +25x +50
A= 50x + 100
You multiply the 2 together 4 5/6 and 2 2/3.
4 5/6=29/6
2 2/3=8/3
you multiply the tops together then the bottoms together
29*8=232
3*6=18
232/18=116/9
PQ // BC
then
Angle P = Angle B, A is common angle the two triangles are similar
AP/AB = AQ/AC
8/18 = 12/ AC
AC = 12 * 18/8 = 27 (your ans: D)
AQ + QC = AC
QC = AC - AQ = 27 - 12 = 15 (if it was required)
tan60 = y/8
y = s tan60 = 8sqrt(3) (B)
Next time, post each question separately.
Answer:
f(-1) = 0
f(2) = 16
Step-by-step explanation:
f(-1) = 4(-1) + 4 = 0
f(2) = 4(2) + 8 = 16
Step-by-step explanation:
Follow PEMDAS
P: Parentheses
E : Exponents
M: Multiplication
D: Division
A: Addition
S: Subtraction
Question 2
