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ELEN [110]
3 years ago
13

MZQRS = [?] HELP PLEASE !!

Mathematics
1 answer:
motikmotik3 years ago
6 0

Answer:

m∠QRS = 49°

Step-by-step explanation:

Complementary angles are angles that add up to 90°. So m∠ABC + m∠QRS = 90°. When you simplify you get 41° + m∠QRS = 90°. So m∠QRS = 49°.

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An equation is given.
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Step-by-step explanation:

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3 years ago
Help me asap!!!!!!!!!!!!
const2013 [10]

Answer:

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Ilia_Sergeevich [38]

Solution:

268

=============================

\sf \bold{ \rightarrow } \ y =  9x^3 + 4x^2 + x + 3

\sf \bold{ \rightarrow } \ \dfrac{dy}{dx} =  \dfrac{d}{dx} (  \ 9x^3 + 4x^2 + x + 3  \ )

| |  \   \mathrm{ If \ y = x^n , \ then  \ \frac{dy}{dx} = nx^{n-1}} \ | |

\sf derivative \  of \  constant \  is \  always \  0  \ || \ \sf\dfrac{d}{dx}\left(a\right)=0 \ ||

solving step wise

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\sf \bold{ \rightarrow } \  \sf  (   3(9x^{3-1}) +2(4x^{2-1}) + (1)(x^{1-1} )+ 0

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\sf \hookrightarrow 268

8 0
2 years ago
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